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MissTica
3 years ago
10

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Mathematics
1 answer:
const2013 [10]3 years ago
7 0
Get photo math app it would help you.
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A circle has a diameter of 26 units. What is the area of the circle to the nearest
denis23 [38]

Answer:

b

Step-by-step explanation:

area = pie x radius(2)

         = 3.142 x 13 (2)

          = 530.998

8 0
3 years ago
Please help with calculations!
ASHA 777 [7]

Resumen de primeros 4 años en Medicina (bioquimica, geneticas, salud publica, ética, etc)

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6 0
4 years ago
The perimeter of a triangle with two equal sides is 71 cm. If its base were lengthened by 6 cm and each leg were shortened by 4
Aleks04 [339]

Your answer would be 17cm.


Because two sides are equal, we can label these two sides x, and the base y, and since the perimeter is 71cm, we can then write the equation 2x + y = 71.


Then we apply the changes made to our sides, so the two equal sides would become x - 4, and the base would become y + 6. We can now set these equal to each other as it states that all sides are equal when this change occurs.


Now we have a pair of simultaneous equations that we can solve with substitution firstly by rearranging the equation x - 4 = y + 6 to get x:


x - 4 = y + 6

+ 4

x = y + 10


Now we can substitute (y + 10) as x into the equation 2x + y = 71 :


2(y + 10) + y = 71

2y + 20 + y = 71

3y + 20 = 71

- 20

3y = 51

÷ 3

y = 17


I hope this helps!

7 0
3 years ago
Six less than the product of 10 and Malik's age<br> Use the variable m to represent Malik's age.
galina1969 [7]
10m-6... Brianliest would be greatly appreciated and would help
3 0
3 years ago
Read 2 more answers
F ( x ) = x − 3 x , g ( x ) = x + 3 , h ( x ) = 2 x + 1 , ( g ⋅ h ⋅ f ) ( x )
DiKsa [7]

Composing functions just means to feed the ouput of the inner one as the input for the outer one.

So, the following writings are equivalent:

(g\circ h \circ f)(x) = g(h(f(x)))

Using the second form, we can see that the first thing to do is to compute f(x), which is given:

f(x) = x-3

This means that we can update the fomula:

(g\circ h \circ f)(x) = g(h(f(x))) = g(h(x-3))

So, now we have to compute h(x-3). Given h(x)=2x+1, we know that h doubles the input and adds one. In this case, the input is x-3, so we have to double this and add one:

h(x-3) = 2(x-3)+1 = 2x-6+1 = 2x-5

So, we have

(g\circ h \circ f)(x) = g(h(f(x))) = g(2x-5)

Similarly, from g(x) = x+3, we understand that g just adds 3 to the input. In this case, the input is 2x-5, so we'll add 3 to this quantity:

g(2x-5) = (2x-5)+3 = 2x-2

So, we finally have

(g\circ h \circ f)(x) = g(h(f(x))) = 2x-2

8 0
3 years ago
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