It's absolutely correct..............
Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
Answer:
X = 3/5
Step-by-step explanation:
2/x=4/5x+2
Find the LCM of the denominator 5x and 1
2/x =4/5x + 2/1
2/x = (4 + 10x)/5x
Cross multiply the equation
2× 5x = (4+ 10x) × x
10x = 4x + 10x^2
Collect like term of the mixed number
10x - 4x = 10x^2
6x = 10x^2
Divide both side by 2x
6x/2x = {10x^2 } / 2x
3 = 5x
Divide both side by the coefficient of x
3/5 = 5x/5
X = 3/5
68 students increased by 125% is
68 + 68(1.25)
68 + 85 = 153
hope it helps
Answer:
It is A.
Step-by-step explanation:
f(x) is exponential and increases at a faster rate as x increases.
g(x) is a linear function and increases at a constant rate of 5.
g(x) increases at a faster rate than f(x) in the interval x = 0 to 1 so D is false.
