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Leno4ka [110]
1 year ago
6

A person is taking a 13​-question ​multiple-choice test for which each question has three answer​ choices, only one of which is

correct. The person decides on answers by rolling a fair die and marking the first answer choice if the die shows 1 or​ 2, the second if it shows 3 or​ 4, and the third if it shows 5 or 6. Find the probability that the person gets fewer than 3 correct answer
Mathematics
1 answer:
motikmotik1 year ago
6 0

The probability of getting fewer than 3 correct answers is 0.1385

<h3>How calculate the probability of getting fewer than 3 correct answers?</h3>

This is a binomial problem with n = 13

Since we are dealing with a binomial probability distribution. We are going to use the binomial distribution formula for determining the probability of x successes:

P(x = r) = nCr . p^r  . q^n-r

total choices = 13 x 3 = 39

p = P(correct answer) = 13/39 =1/3

Given: n = 13, p = 1/3, q = 1- 1/3 = 2/3

Fewer than 3 correct answers mean less than 3 correct answers

P(x<3) = P(x = 0) + P(x=1) + P(x=2)

P(x<3) = (13C0 × (1/3)^0 × (2/3)^13-0) + (13C1 × (1/3)^1 × (2/3)^13-1 + (13C2 × (1/3)^2 × (2/3)^13-2)

         = 0.005138 + 0.0333 + 0.1001

         = 0.1385

Therefore, the probability that the person gets fewer than 3 correct answers is 0.1385

Learn more about binomial distribution on:

brainly.com/question/29220138

#SPJ1

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Answer:

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Step-by-step explanation:

15*12.50= 180

263.85-180=83.85

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Step-by-step explanation:

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Only D is lying.

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3 0
3 years ago
Can someone please help me??
Fantom [35]

Answer:

b=3, y=6

Step-by-step explanation:

Label the 2 equations:

2b +6y= 42 -----(1)

2b +4y= 30 -----(2)

(1) -(2):

(2b +6y) -(2b +4y)= 42 -30

2b +6y -2b -4y= 12

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y= 12 ÷2 <em>(</em><em>÷</em><em>2</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

y= 6

Susbt. y=6 into (2):

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2b +24=30

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2b= 6

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