HETY is a parallelogram.
HT and EY are diagonals. We know that diagonals divides the parallelogram into two equal parts.
So ar(HET) = ar(HTY)
And, ar(HEY) = ar(EYT) now, in AHET, diagonal EY bisects the line segment HT and also the AHET,
∴ar(AHOE) = ar(AEOT)
Similarly in AETY
ar(ΔΕΟΤ) = ar(ΔΤΟΥ)
And in AHTY,
ar(ATOY) = ar(AHOY)
That means diagonals in parallelogram divides it into four equal parts.
Hence Proofed.
Answer:
225 students
Step-by-step explanation:
45 x 5 = 225
Answer:
Choice A. 3.
Step-by-step explanation:
The triangle in question is a right triangle.
- The length of the hypotenuse (the side opposite to the right angle) is given.
- The measure of one of the acute angle is also given.
As a result, the length of both legs can be found directly using the sine function and the cosine function.
Let
denotes the length of the side opposite to the
acute angle, and
be the length of the side next to this
acute angle.
.
Similarly,
.
The longer leg in this case is the one adjacent to the
acute angle. The answer will be
.
There's a shortcut to the answer. Notice that
. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the
angle will be the longer leg. There will be no need to find the length of the opposite leg.
Does this relationship
holds for all acute angles? (That is,
?) It turns out that:
Answer:
The answer is B) 11.
Step-by-step explanation:
We can solve this by making an expression to represent the situation. Let x = the number of student books in the box (what we're looking for):





