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2 years ago

17 is what percent of 68?

1 answer:

3 0

$\frac{17}{68} \times 100\%=\frac{1 \times 17}{4 \times 17} \times 100\%=\frac{1}{4} \times 100\%=\frac{100}{4} \%=25\%$

17 is 25% of 68.

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What is the smaller of the numbers 1 and -10/3

antiseptic1488 [7]

-10/3 is smaller and 1 is bigger.

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1 year ago

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Bank A is lending money at 6.4% interest compounded annually. The rate at Bank B is 6.3% compounded monthly, and the rate at Ban

Ad libitum [116K]

Answer:

$1596

$1597.28

$1598.33

bank A

Step-by-step explanation:

The formula for calculating compound interest:

FV = P (1 + r/m)^mn

FV = Future value

P = Present value

R = interest rate

N = number of years

m = number of compounding

Bank A = $1500(1.064) = $1596

Bank B = $1500( 1 + 0.063/12)^12 = 1597.28

Bank C = $1500( 1 + 0.0635/365)^365 = $1598.33

Bank A pays the least amount of interest

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2 years ago

Translate "Three is less than thirty-seven into a mathematical expression

uysha [10]

3 < 37
I hope this helps you!

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3 years ago

A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa

Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = $\frac{12!}{3! 3! 3! 3!}$

Now,

The Total number of ways in which Remaining cards are distributed = $\frac{40!}{10! 10! 10! 10!}$

So,

Total number of ways of getting 3 picture card and remaining card = $\frac{12!}{3! 3! 3! 3!}$ × $\frac{40!}{10! 10! 10! 10!}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = $\frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }$

∴ The probability = $\frac{\frac{12! 40!}{(3!)^{4} (10!)^{4} }}{\frac{52!}{(13!)^{4} }}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13!)^{4} }{ 52! }$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }$

= $\frac{12!}{(3!)^{4} }$ × $\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= $\frac{479,001,600}{(6)^{4} }$ × $\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

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2 years ago

I will give you brainliest I will give you five stars and I will give you a heart if you can get this correct

BigorU [14]

Answer:

the last one

Hope this helps

-mercury

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2 years ago