Jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
−1
Explanation:
Let's say the set of downs starts at the 20 yard line (maybe the kicking team kicked deep, the receiving team took a knee and so play starts at the 20).
Ok - we're at the 20. First down - they advance 5 yards. So we're now at the 25. We can write that mathematically as:
20 + 5= 25
So the second play they get sacked deep and lose 6 yards. So we subtract 6:
25 − 6=19
So what's the change in yardage for the 2 plays? We are on the 19 and started at the 20, so we can write:
19 − 20= −1
and this makes sense because we know we advanced 5 and fell back 6:
+5 −6 = −1
I agree with -3! Hopefully it did helped you
Answer:
Sally is not right
Step-by-step explanation:
Given the two sequences which have their respective 
terms as following:
Sequence A. 
Sequence B. 
As per Sally, there exists only one number which is in both the sequences.
To find:
Whether Sally is correct or not.
Solution:
For Sally to be correct, we need to put the terms of the respective sequences as equal and let us verify that.
When we talk about terms, 
here is a whole number not a fractional number.
But as per the statement as stated by Sally is a fractional number, only then the two sequences can have a number which is in the both sequences.
Therefore, no number can be in both the sequences A and B.
Hence, Sally is not right.
<span>f(x)=5x+3/6x+7
This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]
If we assume x≠0 , f(6/x) = [30 +3x]/ [36 + 7x]
g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
