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brilliants [131]
3 years ago
11

how can you find products by using the properties. the properties are distributive property, associative property, and commutati

ve property
Mathematics
1 answer:
Ivan3 years ago
3 0
By using distributive property, you can break up the array by its part, For example: 9 x 4
You might be interested in
What’s 3x3x3x3x3x3x3
Artist 52 [7]

Answer:

2,187

Step-by-step explanation:

I used a calculator.

8 0
3 years ago
What is the solution to the equation 3/m+3- m/3-m=m^2+9/m^2-9?
Marina86 [1]
AWNSER D. No solution
5 0
4 years ago
Read 2 more answers
4 chairs and 3 tables together cost ₨ . 2100 and 5 chairs and 2 tables cost Rs.1750. Find the cost of 1 chair and 1 table while
malfutka [58]

Answer:

Cost of one chair  = Rs . 150

Cost of one table = Rs. 500

Step-by-step explanation:

Let number of chairs denote x and no of tables denote y

4x + 3y = 2100 --------------------(i)

5x +2y = 1750 ------------------(ii)

Multiply equation (i) by 2 and (ii) by (-3) and now y will be eliminated.

(i)*2        8x + 6y =  4200

(ii)*(-3)   -<u>15x - 6y = - 5250</u>    {Now, add}

               - 7x     = - 1050

x = -1050/-7

x = Rs. 150

Plug in the value of x inn equation (i)

4*150 + 3y = 2100

600 + 3y = 2100

3y = 2100 - 600

3y = 1500

y= 1500/3

y =Rs 500

5 0
3 years ago
Which equation is the slope-intercept form of the line that passes through (6, –11) and is parallel to the graph of y = –23x + 1
Finger [1]

Answer:

Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 .

Step-by-step explanation:

Given as :

The equation of one line

y = - 23 x + 12

∵ The equation of line in slope-intercept form is

y = m x + c

where m is the slope of line and c is y-intercept

Now, Compare given line with standard line equation

So, The slope of given line = m = - 23

Now, Again

Other line is passing through point (6 , - 11) and is parallel to given line

so, both the lines are parallel

For parallel line condition , Slope of both lines are equal

Let The slope of other line = M

So, M = m = - 23

Now, Equation of other line passing through point (6 , - 11) and slope - 23 in slope-point form

y - y_1 = M × (x -  x_1)

i.e y - ( - 11) = (- 23) × (x - 6)

Or, y + 11 = - 23 × x + 138

Or, y = - 23 x + 138- 11

i.e y = - 23 x + 127

So, The equation of other line  y = - 23 x + 127

Hence, Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 . Answer

8 0
3 years ago
I don’t know how to answer this
oee [108]

Answer:

m∠1=66

m∠3=66

m∠4=114

Step-by-step explanation:

m∠1+m∠2=180

m∠1+114=180

m∠1=66

m∠1=m∠3

66=m∠3

m∠4=m∠2

m∠4=114

5 0
3 years ago
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