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Mrac [35]
3 years ago
7

Find the product. (4p – 6)(4p + 6)

Mathematics
2 answers:
umka2103 [35]3 years ago
8 0
16p^2-36 should be your answer
masha68 [24]3 years ago
7 0

Answer:

The product of (4p – 6)(4p + 6) is ( 16p² - 36 )

Step-by-step explanation:

Let first number is, n₁ = ( 4p - 6 )

Second number is, n₂ = ( 4p + 6 )

We have to find the product of above two numbers. It can be calculated using algebraic identities as :

(a-b)(a+b)=a^2-b^2

In given question, a = 4p and b = 6

So, the product of above two numbers is :

(4p-6)(4p+6)=(4p)^2-(6)^2=16p^2-36

So, the product of (4p – 6)(4p + 6) is ( 16p² - 36 ). Hence, this is the required solution.                  

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List these from least to greatest π2, 12, √80
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Answer:

π2,√80,12

Step-by-step explanation:

π2= 6.28

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3 years ago
If 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), w
Yuliya22 [10]

The value of a is 80

Step-by-step explanation:

The distance of a point (x_0,y_0) from the y-axis can be written as

d_y = |x_0|

because the x-coordinate of the y-axis is zero.

Similarly, the distance of a point (x_0,y_0) from the x-axis can be written as

d_x=|y_0|

Since the y-coordinate of the x-axis is zero.

In this problem:

- The distance of the point A (−30, −45) from the y-axis can be written as

d_A = |-30|=30

- The distance of point B (a,a) from the x-axis can be written as

d_B = |a| = a

Since a>0.

We are told that 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), which means

\frac{2}{3}d_A = \frac{1}{4}d_B

Therefore,

\frac{2}{3}(30)=\frac{1}{4}a

And solving for a,

20=\frac{1}{4}a\\a=80

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

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