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2 years ago

Find x in the triangle below. Round your answer to the nearest tenth.

Mathematics

1 answer:

jonny [76]2 years ago

6 0

Answer:

Step-by-step explanation:

Remark

x is opposite the 90 degree angle. It is the hypotenuse.
13 makes up the 57 degree angle. It is the side adjacent.
The adjacent side and the hypotenuse define the cos(theta).

Formula

cos(theta) = adjacent side / hypotenuse

Givens

Theta = 57 degrees

Hypotenuse = x

Side adjacent = 13

Solution

Cos(57) = 13 / x Multiply both sides by x
x*cos(57) = 13 Divide by cos(theta)
x = 13/cos(57)
x = 13 / cos(57)
cos(57) = 0.5446
x = 13/ 0.5446
x = 23.87

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Answer:

A'(5.5, -4.2), B'(7.5, -9.2), C'(3.5, -3.2)

Step-by-step explanation:

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3 years ago

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3 years ago

Question 2 options:

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2 years ago

What should be the next number in the following series? 1 2 8 48 384

cluponka [151]

1
1 · 2 = 2
2 · 4 = 8
8 · 6 = 48
48 · 8 = 384
384 · 10 = 3840
3840 · 12 = 46080
46080 · 14 = 645120
...

$a_1=1;\ a_n=a_{n-1}\cdot(2n-2)$

3 0

3 years ago

2. You throw a softball straight up into the air at a velocity of 30 feet per second. You release the softball at a height of 5.

nadya68 [22]

Answer:

$-16t^2+30t+5.8$

Step-by-step explanation:

We are given that

Initial velocity=30 ft/s

Initial position= $s_0=5.8 ft$

We have to write a mathematical model for height of the softball by using the position equation

The position equation on Earth's surface is given by

$h(t)=-16t^2+v_0t+s_0$

Where $v_0=$ Initial velocity

$s_0$ =Initial position

Substitute the values in the equation then, we get

$h(t)=-16t^2+30t+5.8$

Hence, the mathematical model for height of the softball is given by

$-16t^2+30t+5.8$

5 0

3 years ago