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hammer [34]
3 years ago
8

10x - 15 = 12x - 101

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
8 0
10x - 15 = 12x - 101

Add 15 on both sides

10x = 12x - 86

Subtract 12 on both sides

-2x = -86

Divide -2 on both sides

x = 43

I hope this helps! :)
GenaCL600 [577]3 years ago
4 0
<span>-49 + -2x + 12x = 101 + -12x + 12x Combine like terms: -2x + 12x = 10x -49 + 10x ... 101 + 49 = 150 10x = 150 Divide each side by '10'. x = 15 Simplifying x = 15 </span><span>
</span>
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-7(8+7v)= -5+2v solve the equation
Alborosie

Answer:

V=-1

Step-by-step explanation:

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How much is 1 in 100,000,000 as a percentage
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The product of two numbers is 240. The first number is 8 less than the second number. Write an equation can be used to find x
DaniilM [7]

Answer:

The equation x = y-8

The equation  (y-8) y = 240

The first number x = 12 and second number y =20

Step-by-step explanation:

<u>Explanation</u>:-

<u>Step(l)</u>:-

Let 'x' be the first number and 'y' be the second number

Given the product of two numbers is 240

Given  data        x y = 240 …(l)

Given data the first number is 8 less than the second number.

                       x = y-8...(ll)

Substitute (ll) in equation (l) , we get

                           (y-8) y = 240

                           y^{2} -8y -240 =0

                            y^{2} -20y+12y -240 =0

                           y(y -20)+12(y -20) =0

                           (y +12)(y -20) =0

                          y = -12 and y = 20

              Y= -12 is not satisfied

              we can choose y = 20

<u>Step(ll):</u>-

Given data x =y-8

  substitute value y = 20 in x = y -8

                                             x = 20-8 = 12

<u>Final answer</u>:-

The first number x = 12 and second number y =20

4 0
3 years ago
192/38 with remanders
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3 0
2 years ago
Read 2 more answers
In the problem below, AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9. Is
Oksi-84 [34.3K]

Answer:

<em>When both the conditions hold true, F is prime.</em>

Step-by-step explanation:

AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9.

  AB

+ CD

--------

  EF

1st condition, B and D are consecutive.

Adding B and D gives us F.

Possible values can be (F being the unit value after adding not considering the carry over):

B + D = F

1+2=3

2+3=5

3+4=7

4+5=9

5+6=1

6+7=3

7+8=5

8+9=7

Here F is not prime (because 9 is not prime).

Now, let us consider the 2nd condition as well.

i.e. C = 8

For the following

  AB

+ CD

--------

  EF

C is 8 then A must be 1 because any value other than 1 for A will make the sum of A and C greater than 9 and there will be a carry which is not the case here.

So, E = 8 + 1 = 9

Now, B  and D are consecutive and can not be 1, 8 or 9.

So, possible values are:

B + D = F

2 + 3 = 5

3 + 4 = 7

Here F is prime.

So, when both the conditions hold true, F is prime.

3 0
2 years ago
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