1 Subtract <span>11</span> from both sides
<span>y-1={3}^{x}<span>y−1=<span>3<span><span>x</span><span></span></span></span></span></span>
2 Use Definition of Common Logarithm: <span>{b}^{a}=x<span><span>b<span><span>a</span><span></span></span></span>=x</span></span> if and only if <span>log_b(x)=a<span>lo<span>g<span><span>b</span><span></span></span></span>(x)=a</span></span>
<span>\log_{3}{(y-1)}=x<span><span><span>log</span><span><span>3</span><span></span></span></span><span>(y−1)</span>=x</span></span>
3 Switch sides
<span><span>x=\log_{3}{(y-1)}<span>x=<span><span>log</span><span><span>3</span><span></span></span></span><span>(y−1)
HOPE THIS HELPS!!! will it?
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Answer:
<u>Option A</u>
Step-by-step explanation:
To reflect line segment BC over line m, BB' will be perpendicular to the line m
and line m bisector of BB'.
<u>So, the correct answer is option A</u>
A) Line m is the perpendicular bisector of line segment BB' and the line segment CC'
<u>Option b is wrong</u> , it is impossible for the line B'C' to be perpendicular to line BC. B'C' is the image of BC.
<u>Both option c and d is wrong</u> because the perpendicular distance from b to the line m not equal to the perpendicular distance from c to the line m.
Answer:
C
Step-by-step explanation:
First is the quadratic equation because (x+4) is squared so we have a parabola graph
Second and third are equations of a lines because we have only x in the equations
...so choices B and C have parabola ,line, line
The parabola has the condition x< -3 since we have a "less then" sign the bubble has to be empty on the parabola line on the graph C
What is 7, 14, 3, 14, 0, 1, 14, 5, 14, 16, 0 from least to greatest
blagie [28]
0,0,1,1,1,3,4,4,5,14,14,14,14,16,17
9.35 times 10 to the second power