So just your normal equation.
We need to isolate x alone.
First lets write out our equation
3 +7x = 12
Lets do this step by step.
first subtract 3 from both sides.
3 + 7x = 12
-3 = -3 it cancels out on the left side and we solve on the right side.
*************
7x = 9
second we divide both sides by 7
7x = 9
÷7 = 7 we got the x alone and we just write 9/7 as our answer.
x = 9/7
Or as a decimal.
9/7 could be <span>1.28571428571429
</span>
Either will work.
x = 9/7
or
x = <span>1.28571428571429
</span>
Have a nice day. :)
The point (-2, 5) is not included in the solution area
<h3>The graph of the inequalities</h3>
The system of inequalities is given as:
y > 5x + 5
y > -2x+1
See attachment for the graph.
Since the inequalities use the greater than symbol, then the lines of the inequalities would be a dotted line and the upper part would be shaded
<h3>The solution area</h3>
The point is given as:
(-2, 5)
The point (-2, 5) is not in the shaded area of the system of inequalities
Hence, the point is not included in the solution area
Mathematically, we have:
5 > 5 * -2 + 5 ⇒ 5 > -5 --- true
5 > -2 * -2 +1 ⇒ 5 > 5 --- false
Since both inequalities are not true, then the point is justified
Read more about system of inequalities at:
brainly.com/question/19526736
#SPJ1
Answer:
1) 48
C) It corresponds to the 48-degree angle
Step-by-step explanation:
k║l
1) <1 = 48
because corresponding angles are equal
Why?
C) It corresponds to the 48-degree angle
Answer:
4
Step-by-step explanation:
9:8 = 4x+2:4x
36x = 32x + 16
x = 4
This isn't an identity, so I assume you have to solve the equation.
(1 - sin(2<em>A</em>)) (1 + cot(2<em>A</em>)) = cot(2<em>A</em>)
1 - sin(2<em>A</em>) + cot(2<em>A</em>) - sin(2<em>A</em>) cot(2<em>A</em>) = cot(2<em>A</em>)
1 - sin(2<em>A</em>) - cos(2<em>A</em>) = 0
sin(2<em>A</em>) + cos(2<em>A</em>) = 1
Multiply both sides by 1/√2, which we want to do because cos(<em>π</em>/4) = sin(<em>π</em>/4) = 1/√2. This gives
cos(<em>π</em>/4) sin(2<em>A</em>) + sin(<em>π</em>/4) cos(2<em>A</em>) = 1/√2
Then condense the left side as
sin(2<em>A</em> + <em>π</em>/4) = 1/√2
2<em>A</em> + <em>π</em>/4 = sin⁻¹(1/√2) + 2<em>nπ</em> <u>or</u> 2<em>A</em> + <em>π</em>/4 = <em>π</em> - sin⁻¹(1/√2) + 2<em>nπ</em>
(where <em>n</em> is any integer)
2<em>A</em> + <em>π</em>/4 = <em>π</em>/4 + 2<em>nπ</em> <u>or</u> 2<em>A</em> + <em>π</em>/4 = 3<em>π</em>/4 + 2<em>nπ</em>
2<em>A</em> = 2<em>nπ</em> <u>or</u> 2<em>A</em> = <em>π</em>/2 + 2<em>nπ</em>
<em>A</em> = <em>nπ</em> <u>or</u> <em>A</em> = <em>π</em>/4 + <em>nπ</em>
