Question

Solve the system algebraically. Check your work.

Answer 1

x=2,y=0

plug it in and check.

Answer 2

Answer:

x=2 and y=0 is the required result.

Step-by-step explanation:

We have been given system of equations:

$5x+2y=10$     (1)

And $3x+2y=6$      (2)

We will use elimination method:

Multiply 1st equation by 3 and 2nd equation by 5 we get:

$15x+6y=30$      (3)

$15x+10y=30$      (4)

Now subtract  (4) from (3) we get:

$-4y=0$

$y=0$

Now, put y=0 in (1) equation:

$5x+2(0)=10$

$5x=10$

$x=2$

Hence, x=2 and y=0