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3 years ago

Need help!! ASAPP! With number #4thx <3

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

5 0

Answer:

Clean and Bright

Step-by-step explanation:

For soapy suds, you would do 13×12, would would give you only 156 sq inches. However, with Clean and Bright, you would do 9×13×8 since it is three dimensional. This would give you 936 cubic inches, meaning it holds the most detergent.

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Use the following image to assist in your answer. a = - 6 - 9 - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

$c^2 = 4^2 + 6^2$

$c^2 = 16 + 36$

$c^{2}$ = 52

Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

$a = \frac{72}{8}$

a = 9

Verifying :

$b^2 = 6^2 + a^2$

$b^2 = 36 + 81$

$b^2 = 117$

$b^{2}$ = 117

The biggest one :

$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

8 0

2 years ago

Please help me anyone ???????

tester [92]

Probability =
(number or amount of possible successes)(total number or amount of possible outcomes)

Area of any circle is (pi) x (radius squared)

Area of the whole board = (pi) x (13 squared) = 169 pi square inches

Area of the shaded region = (pi) x (5 squared) = 25 pi square inches

Probability = (success area) / (total possible area) = 25pi/169pi = 0.15 (rounded)

Notice that if you do it my way ... keep 'pi' in the fraction ... you don't even
need to know what the value of 'pi' is, because there's one in the top and
bottom of the fraction, and they cancel.

6 0

3 years ago

Please help for number 68!!

kiruha [24]

Answer:

the answer would be F 1 mile.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

There are 80 sixth graders at Wilson Middle School. Only 70% of the sixth graders will attend the morning assembly. How many six

zysi [14]