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3 years ago

Did Tom make a mistake in solving the problem? Yes or No?

Mathematics

2 answers:

JulsSmile [24]3 years ago

7 0

Answer:

No tom did not

Step-by-step explanation:

Sliva [168]3 years ago

6 0

Answer:I do not think Tom made a mistake

Step-by-step explanation:

Someone double check me

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3x-(2x-1)=7x-(3*5x)+(-x+24)

Paraphin [41]

Answer:

$\boxed{\boxed{\sf x=\frac{23}{10}}\: \sf or \:\boxed{x=2.3}}$

_________________

$\boxed{\sf Step\: By\:Step:- }$

$\sf 3x-\left(2x-1\right)=7x-\left(3\times \:5x\right)+\left(-x+24\right)$

Remove the parentheses:

$\to\sf 3x-\left(2x-1\right)=7x-3\times \:5x-x+24$

Combine like terms:

$\sf ^*7x-x=6x$

$\to\sf 3x-\left(2x-1\right)=6x-3\times \:5x+24$

Multiply 3 and 5x = 15x:-

$\to\sf 3x-\left(2x-1\right)=6x-15x+24$

Combine like terms:

$\sf ^*6x-15x=-9x$

$\to\sf 3x-\left(2x-1\right)=-9x+24$

Expand: 3x-(2x-1)= x+1

$\to\sf x+1=-9x+24$

Subtract 1 from both sides:

$\to\sf x+1-1=-9x+24-1$

$\to\sf x=-9x+23$

Add 9x to both sides:

$\to\sf x+9x=-9x+23+9x$

$\to\sf 10x=23$

Divide both sides by 10:

$\to\sf \cfrac{10x}{10}=\cfrac{23}{10}$

$\to\sf x=\cfrac{23}{10}$

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