Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
Subtract 110 dollars from 77 dollars to get your answer of 33 dollars
Hope this helps
Answer:
i dont know im wondering to o-o
Step-by-step explanation:
Answer: No! This is not a function!
Step-by-step explanation:
Functions. Terms. Domain - The set of all inputs of a relation or function. Function - A relation in which each input has only one output. Often denoted f (x). Horizontal Line Test - If every horizontal line you can draw passes through only 1 point, x is a function of y.
Answer:
Here is your answer C
Step-by-step explanation:
