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dalvyx [7]
3 years ago
6

1. Oscar entered y=−0.4^x+3 into an online graphing tool.

Mathematics
2 answers:
cluponka [151]3 years ago
7 0
___Brainliest if helped

1.He plotted y= -(0.4^x)+3 
He did not bracket properly so this is the graph. 

2.
<span>C. The graph decreases from left to right.
</span><span>D. The point ​ (4, 1.72) ​ is on the graph.
</span><span>E. The graph has a y-intercept only.

</span><span>D. Quadrants I and IV only 
Imagine a J shape from quad 4 extend to quad 1. </span>
krok68 [10]3 years ago
6 0

Answer:

1.  y = -(0.4^x)+3 

2. C and E

3. D

Step-by-step explanation:

1.  y = -(0.4^x)+3 

Exponentials goes first, so the first operation is 0.4^x; then goes multiplication, that means the next operation is (-1)*(0.4^x); and finally goes the addition

2. y-intercept: (0, 2.4)

slope: -0.08

function: y = -0.08*x + 2.4

where y  is the price and x  are the weeks

C. The graph decreases from left to right. -> negative slope

E. The graph has a y-intercept only. -> all equations of a line has only one y-intercept

3. D. Quadrants I and IV only 

y-variable starts at a negative value and x-variable can only assume values greater than zero

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A. \left[\begin{array}{cc}0.93&0.07&\\0.01&0.99&\end{array}\right]

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Step-by-step explanation:

(a) The transition matrix for the information is

                C        S

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and this gives us

         (0.85    0.15)

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Answer:

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

(b) The amount of pure acid in 60 oz of 25% acid solution is 15 oz.

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- The solution is a mixture of two or more substances

- A container of liquid contains 60 oz of solution

- The solution contains pure acid by different concentrations

- (a) 20% (b) 25% (c) 30% (d) 50%

- We want to find the number of ounces of the pure acid in each

 concentration

- Assume that the solution is 100%

- That means 100% represents 60 oz of solution

a)

- The percentage of pure acid is 20%

∵    solution     ⇒     pure acid

        100%               20%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*20}{100}= 12

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

b)

- The percentage of pure acid is 25%

∵    solution    ⇒      pure acid

        100%               25%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*25}{100}= 15

(b) The amount of pure acid in 60 oz of 25% acid solution is 15oz.

c)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               30%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*30}{100}= 18

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

d)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               50%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*50}{100}= 30

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

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