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IgorC [24]
3 years ago
15

7 of every 20 employees at v&b bank company are between the ages of 20 and 30 if there are 13220 employees at B&B Bank c

ompany how many are between the ages of 20 and 30
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
4 0
Hello! 7/20 employees are between the ages of 20 and 30. That's 35% of employees, because 7/20 is 0.35 and 0.35 * 100 is 35. To find the amount of employees in that age range, all you have to do is multiply 35% by the total number of employees. 13,220 * 35% (0.35) is 4,627. There. 4,627 employees that work at the B&B bank are between the ages of 20 and 30.
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A cereal box filling machine is designed to release an amount of 16 ounces of cereal into each box, and the machine’s manufactur
Paraphin [41]

Using the z-distribution, it is found that since the p-value is less than 0.05, there is evidence that the mean amount of cereal in each box is different from 16 ounces at 0.05 significance.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the mean is not different to 16 ounces, that is:

H_0: \mu = 16

At the alternative hypothesis, it is tested if the mean is different, hence:

H_1: \mu \neq 16

<h3>What is the test statistic?</h3>

The test statistic is:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

In which:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • \sigma is the standard deviation of the population.
  • n is the sample size.

The parameters for this problem are:

\overline{x} = 15.75, \mu = 16, \sigma = 1.46, n = 150.

Hence:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{15.75 - 16}{\frac{1.46}{\sqrt{150}}}

z = -2.1

<h3>What is the p-value and the conclusion?</h3>

Using a z-distribution calculator, for a two-tailed test, as we are testing if the mean is different of a value, with z = -2.1, the p-value is of 0.0357.

Since the p-value is less than 0.05, there is evidence that the mean amount of cereal in each box is different from 16 ounces at 0.05 significance.

More can be learned about the z-distribution at brainly.com/question/16313918

#SPJ1

3 0
2 years ago
Please help ?? =) ^-^
katrin2010 [14]

17 + 6 = 23

She has 23 quarters.

Each games cost 2 quarters.

23/2 = 11.5

She can play 11 games and has 1 quarter leftover.

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3 years ago
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Teddy was having trouble fitting into his clothes due to weight gain. In January, he weighed 180 lbs 6 oz. He gained 3 lbs 9 oz,
barxatty [35]
He weighs 196 lbs and 6 ounces. if you add the pounds (180 to 3, 5, 6)you get 194. then you add he ounces, and remember that there are 16 ounces in a pound and 8 ounces in a cup, (6 to 9, 12, 11) you get 2lbs and 6 ounces. then you add the 2 extra pounds to the 194 and you get, all together, 196 lbs and 6 ounces.
7 0
3 years ago
Part of the graph of the function f(x) = (x – 1)(x + 7) is shown below. Which statements about the function are true?
BaLLatris [955]

Answer:

the answers are B,C,D

Step-by-step explanation:

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A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the
leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em />I \to<em> I-Beam</em>

<em />d_I \to<em> distance between I beam and the bridge</em>

<em />b \to<em> distance between each I beam</em>

<em />

Given that:

I = \frac 34 ft\\

d_I = 3 ft

<em />Length = 55ft\ 6in<em> --- length of the  bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

L_1 = 6 \times I

L_1 = 6 \times \frac 34

L_1 = \frac {18}4

L_1 = 4.5ft

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

d_1 =2 \times d_I

d_1 =2 \times 3ft

d_1 =6ft

There are 5 spaces between the I-beams

So, the length of the total spaces is:

L_2 = 5 \times b

L_2 = 5b

The total length is:

Length = L_1 + d_1 + L_2

So, we have:

4.5ft + 6ft + 5b = 55ft\ 6in

Collect like terms

5b = 55ft\ 6in - 4.5ft - 6ft

5b = 44.5ft\ 6in

Convert inches to feet

5b = 44.5ft\ + \frac{6}{12}ft

5b = 44.5ft\ + 0.5ft

5b = 45ft

Divide both sides by 5

b = 9ft

<em>Hence, the distance (b) between each beam is 9ft.</em>

Read more about lengths at:

brainly.com/question/22059747

3 0
3 years ago
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