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uranmaximum [27]
2 years ago
13

N

Mathematics
1 answer:
anygoal [31]2 years ago
7 0

Answer:

Area =22/7×12×12

=281.142cm square

Step-by-step explanation:

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CHECK YOUR UNDERSTANDING
Mademuasel [1]
If Kyle has invested $20,000 of the total $160,000 invested, that means the other give investors invested $140,000. Divide the about they invested by the total amount invested, and you will get .875. That is equal to 87.5%. The five investors own 87.5% of the business.
5 0
3 years ago
The product of 3.41 and 8.5 will have how many decimal places?
Aleks04 [339]
Hello! 

3.41 × 8.5 = 28.985

The product of 3.41 and 8.5 is 28.985, which has three decimal places. 

3 0
3 years ago
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
avanturin [10]
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900

There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20

The price of an advance ticket was 20.
The price of a same-day ticket was 15.
6 0
3 years ago
Need help show your work
Ronch [10]
The answer should be 1/3
Cause u take 2/5=base*6/5
Divide 6/5 from both sides
The answer should be 1/3
8 0
3 years ago
Find the missing side lengths. Leave your answers as radicals in simplest form.
Citrus2011 [14]

This is the isosceles right triangle, the diagonal of a square, the thing that so upset the Pythagoreans. The two sides and diagonal of a square are in ratio 1:1:\sqrt{2} so we get


u = v =  8


We could have also gotten this using Trig:


u = (8 \sqrt{2}) \sin 45^\circ = 8 \sqrt{2}/\sqrt{2} = 8


v = (8\sqrt{2})\cos 45^\circ = 8


Or by recognizing u=v because remaining angle is 45 so this must be isosceles so


u^2 + u^2 = (8 \sqrt{2})^2


2u^2 = 2 (8^2)


u = 8

8 0
3 years ago
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