Answer:
8
Step-by-step explanation:
100 = x^2 + AC^2
17^2 = AC^2 + (21 - x)^2
289 = AC^2 + 21^2 + x^2 - 2*21*x
289 =<u> AC^2</u> + 441 +<u> x^2</u> - 42x
from 1st equation AC^2 + x^2 = 100
289 = 441 + 100 - 42x
289 = 541 - 42x
42x = 541 - 289 = 252
x = 252/42 = 6
so AC^2 = 100 - 6^2 = 100 - 36 = 64
AC = 8
Answer:
99.1 is the 90th percentile of these scores.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 85
Standard Deviation, σ = 11
We are given that the distribution of score is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.90
Calculation the value from standard normal z table, we have,

Putting values, we get,
Thus, 99.1 is the 90th percentile of these scores.
Answer:
number of $20 bill = 4
Number of $5 bill = 5
Step-by-step explanation:
Given that:
Total number of $5 and $20 bills = 9
Let :
Number of $5 bills = x
Number of $20 bills = y
Combined worth of all bills = $105
x + y = 9 - - - (1)
5x + 20y = 105 - - - (2)
From (1)
x = 9 - y
Substitute x = 9 - y into (2)
5(9 - y) + 20y = 105
45 - 5y + 20y = 105
15y = 105 - 45
15y = 60
y = 60/15
y = 4
x = 9 - y
x = 9 - 4 = 5
Hence,
number of $20 bill = 4
Number of $5 bill = 5
Remember
(x^m)/(x^n)=x^(m-n)
(q^(33/4))/(q^8)=q^((33/4)-8)
what is 33/4-8?
33/4-8=33/4-32/4=1/4
result is
q^1/4 or
![\sqrt[4]{q}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Bq%7D%20)
answer is