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LenKa [72]
3 years ago
14

At a fabric store, the probability that a customer buys thread is 0.15. The probability that a customer buys a needle given that

the customer buys thread is 0.25.
Which statement is true?

A. Buying a needle and buying a thread are independent events.
B. Every customer who buys a thread also buys a needle.
C. Buying a needle and buying a thread are dependent events.
D. The probability that a customer buys a needle and thread is a 0.10.
Mathematics
1 answer:
Sveta_85 [38]3 years ago
8 0

Answer:

The correct statement is:

C. Buying a needle and buying a thread are dependent events.

Explanation:

The first statement is incorrect because the given events are dependent on each other because the probability that a customer buys a needle given that the customer buys thread is 0.25.

The second statement is incorrect because we cannot say all those who buy a thread also buy a needle.

The fourth statement is incorrect because the probability that a customer buys a needle and thread is 0.25 \times 0.15=0.0375



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Dima020 [189]

Answer:

Step-by-step explanation:

a) sub in 600 for 6

600-25/40 =14.375

b) switch x and y

x=y-25/40

Solve for y

40x=y-25

y=40x+25

c)Plug in 2.5 for z(x)

2.5= x-25/40

100=x-25

x=125

8 0
3 years ago
What is an equation of the line through (0,-3) with slope 2\5
baherus [9]
M=2/5  , (0,3)
use y= mx+c ,   find c first.
-3 = (2/5) 0 + c
c = -3
Thus the equation will be y=(2/5)x - 3.
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7 0
2 years ago
EThe graph of a quadratic function passes through the points (6,0) and (p,0). The maximum point
MA_775_DIABLO [31]

Answer:

p = - 5

Step-by-step explanation:

The vertex of the function is (0.5, 30.25 )

Since the roots are (6, 0) and (p, 0) then the axis of symmetry is vertical

with equation x = 0.5

The axis of symmetry passes through the midpoint of the roots, thus

\frac{6+p}{2} = 0.5 ( multiply both sides by 2 )

6 + p = 1 ( subtract 6 from both sides )

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6 0
3 years ago
Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1
svet-max [94.6K]

Answer:

a) 0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

b) 0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.0 ounces and a standard deviation of 1.1 ounces.

This means that \mu = 8, \sigma = 1.1

(a) If 5 potatoes are randomly selected, find the probability that the mean weight is less than 9.3 ounces?

n = 5 means that s = \frac{1.1}{\sqrt{5}} = 0.4919

This probability is the pvalue of Z when X = 9.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{9.3 - 8}{0.4919}

Z = 2.64

Z = 2.64 has a pvalue of 0.9959

0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

(b) If 6 potatoes are randomly selected, find the probability that the mean weight is more than 9.0 ounces?

n = 6 means that s = \frac{1.1}{\sqrt{6}} = 0.4491

This probability is 1 subtracted by the pvalue of Z when X = 9. So

Z = \frac{X - \mu}{s}

Z = \frac{9 - 8}{0.4491}

Z = 2.23

Z = 2.23 has a pvalue of 0.9871

1 - 0.9871 = 0.0129

0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

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