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LenKa [72]
4 years ago
14

At a fabric store, the probability that a customer buys thread is 0.15. The probability that a customer buys a needle given that

the customer buys thread is 0.25.
Which statement is true?

A. Buying a needle and buying a thread are independent events.
B. Every customer who buys a thread also buys a needle.
C. Buying a needle and buying a thread are dependent events.
D. The probability that a customer buys a needle and thread is a 0.10.
Mathematics
1 answer:
Sveta_85 [38]4 years ago
8 0

Answer:

The correct statement is:

C. Buying a needle and buying a thread are dependent events.

Explanation:

The first statement is incorrect because the given events are dependent on each other because the probability that a customer buys a needle given that the customer buys thread is 0.25.

The second statement is incorrect because we cannot say all those who buy a thread also buy a needle.

The fourth statement is incorrect because the probability that a customer buys a needle and thread is 0.25 \times 0.15=0.0375



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Diagram 5 shows a triangle ABD such that AD = 17 cm, AB = 10 cm and BD = 21 cm. The straight line AC is perpendicular to the str
OlgaM077 [116]

Answer:

8

Step-by-step explanation:

100 = x^2 + AC^2

17^2 = AC^2 + (21 - x)^2

289 = AC^2 + 21^2 + x^2 - 2*21*x

289 =<u> AC^2</u> + 441 +<u> x^2</u> - 42x

from 1st equation AC^2 + x^2 = 100

289 = 441 + 100 - 42x

289 = 541 - 42x

42x = 541 - 289 = 252

x = 252/42 = 6

so AC^2 = 100 - 6^2 = 100 - 36 = 64

AC = 8

7 0
3 years ago
The scores for a certain test of intelligence are normally distributed with mean 85 and standard deviation 11. Find the 90th per
jonny [76]

Answer:

99.1 is the 90th percentile of these scores.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 85

Standard Deviation, σ = 11

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.90

P( X < x) = P( z < \displaystyle\frac{x - 85}{11})=0.90  

Calculation the value from standard normal z table, we have,  

P(z \leq 1.282) = 0.90

Putting values, we get,

\displaystyle\frac{x - 85}{11} = 1.282\\\\x = 99.1

Thus, 99.1 is the 90th percentile of these scores.

5 0
3 years ago
= 118
oee [108]

Answer:

number of $20 bill = 4

Number of $5 bill = 5

Step-by-step explanation:

Given that:

Total number of $5 and $20 bills = 9

Let :

Number of $5 bills = x

Number of $20 bills = y

Combined worth of all bills = $105

x + y = 9 - - - (1)

5x + 20y = 105 - - - (2)

From (1)

x = 9 - y

Substitute x = 9 - y into (2)

5(9 - y) + 20y = 105

45 - 5y + 20y = 105

15y = 105 - 45

15y = 60

y = 60/15

y = 4

x = 9 - y

x = 9 - 4 = 5

Hence,

number of $20 bill = 4

Number of $5 bill = 5

6 0
3 years ago
John's teacher wants to buy giant cookies for the entire class. If cookies cost $2.50 each, write an equation that shows how man
Anna11 [10]
2.5x=40  .. 40/2.5 = 16 . x=16
4 0
4 years ago
What is the simplified form of the expression?
SIZIF [17.4K]
Remember
(x^m)/(x^n)=x^(m-n)

(q^(33/4))/(q^8)=q^((33/4)-8)
what is 33/4-8?
33/4-8=33/4-32/4=1/4

result is
q^1/4 or \sqrt[4]{q}

answer is q^{ \frac{1}{4} }
8 0
3 years ago
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