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ryzh [129]
3 years ago
5

Which one of the following statements is true of perpendicular lines? A. They intersect to form an obtuse angle. B. They interse

ct to form an acute angle. C. They never intersect. D. They intersect at one point.
Mathematics
1 answer:
grin007 [14]3 years ago
3 0
The correct answer among the choices listed above is option D. The statement that is true for perpendicular lines is that they intersect at one point. Also, they form a right angle or an angle equal to 90 degrees. Hope this answers the question.
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Please help me with 8, 9, and 10 thanks! Show work too
Harrizon [31]
In 8, 9, 10, all the triangles are similar, meaning corresponding sides have the same ratio.

8. hypotenuse / (short side) = 25/x = x/9
  x² = 25*9 = 5²×3²
  x = √(5²×3²) = 5*3 = 15

9. (long side) / (short side) = x/7 = 9/x
  x² = 7*9
  x = √(9*7) = 3√7

10. (short side) / (long side) = x/48 = 48/64
  x = 48²/64 = 36
3 0
3 years ago
the mean average distance that jack runs in his last 10 runs is 5.7 miles. work out the distance that he would need to make this
ziro4ka [17]

Answer:

9 miles

Step-by-step explanation:

mean is calculated as

mean = \frac{sum}{count} , then

\frac{sum}{10} = 5.7 ( multiply both sides by 10 )

sum = 57

let x be the distance he needs to cover so mean is 6 , that is

\frac{sum+x}{11} = 6 ( multiply both sides by 11 )

sum + x = 66 , that is

57 + x = 66 ( subtract 57 from both sides )

x = 9

That is he would have to run 9 miles

3 0
2 years ago
PLEASEEEE HELP!!!<br> Which equation should you solve to find x?
ziro4ka [17]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The tables represent two linear functions in a system.
stich3 [128]

Answer:

how?

Step-by-step explanation:

i didnt get this question

3 0
3 years ago
A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat
jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.  

We are given a function (corrected)

N(t) = 20(t^2-lnt^2)+ 30

N(t) = 20(t^2-2lnt)+ 30

(a)

First, we take its derivative

N'(t) = 20(2t-\frac{2}{t})

Solve N'(t)=0

20(2t-\frac{2}{t})=0

Simplifying

2t^2-2=0

Solving for t

t=1\ ,t=-1

Only t=1 belongs to the valid interval 1\leqslant t\leqslant 15

Taking the second derivative

N''(t) = 20(2+\frac{2}{t^2})

Which is always positive, so t=1 is a minimum

(b)

N(1)=20(1^2-2ln1)+ 30

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

N(15)=20(15^2-2ln15)+ 30

N(15)=4391.7 is a maximum

7 0
3 years ago
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