Answer:
Deceleration = 5.7 m/s²
Explanation:
We are given;
Deceleration of the car; d = -3.15 m/s²
Angle of inclination; θ = 9.7°
Coefficient of friction will be calculated as; μ = d/g = 3.15/9.81 = 0.3211
Now,the acceleration would be gotten from the formula;
a = g (sin(θ) + μ cos(θ))
Plugging in the relevant values to give;
a = 9.81[sin 9.7 + (0.3211 × cos (9.7)]
sin 9.7 and cos 9.7 are in radians, thus we have;
a = 9.81(-0.2718 + (0.3211 × -0.9624))
a = -5.7 m/s²
Negative acceleration means a Deceleration of 5.7 m/s²
The electrostatic force acting on a charge q is given by
where E is the electric field's intensity.
In our problem, the particle is an electron, so its charge is
. We know the intensity of the force, so we can find the magnitude of the electric field at the point where the electron is located:
where the negative sign means that the force and the electric field have opposite direction, because the charge is negative.
Explanation:
30km/h -->
A-----------------B
<-- 50km/h
Displacement = 0 (initial and final point are the same)
Distance=2AB
Average Speed=37.5km/h
Explanation:
The expression is :
A =[LT], B=[L²T⁻¹], C=[LT²]
Using dimensional of A, B and C in above formula. So,
Comparing the powers both sides,
2n+m=1 ...(1)
2m-n=1 ...(2)
Now, solving equation (1) and (2) we get :
Hence, the correct option is (E).