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stiv31 [10]
3 years ago
12

A shopper at the Fries’ market place pushes a 13.0-kg shopping cart at a constant velocity for a distance of 58.7 m on a level s

urface. He pushes in a direction 24.50 below the horizontal. A 53.8 N frictional force opposes the motion of the cart. (a) What is the magnitude of the force that the shopper exerts on the cart? (b) What is the work done by the pushing force? (c) What is the work done by the frictional force? (d) What is the work done by the gravitational force?
Physics
1 answer:
Gnom [1K]3 years ago
4 0

We do a force summatory, then,

a) \sum F=0

Fcos(24.5)-F_f= 0

Fcos(24.5)-53.8= 0

F= \frac{53.8}{cos(24.5)}

F=59.12 N

(b) For the Work we need the equiation with the variable in X.

W= F (d cos(24.5))

W= 59.12 (58.7) cos 24.5

W=3158.1 J

(c) However the Frictional Force Work,

W= F_f d

W= -53.8(58.7)

W=-3158.1 J

(d) Now the work by gravity

W_g= F d (cos(90))=0

W_g=0

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2 years ago
a steam engine works on its vicinity and 285 k heat is released with the help of 225 degree centigrade energy absorbed to the sy
Studentka2010 [4]

The efficiency of the steam engine is 78.9%.

<h3>What is the efficiency of a machine?</h3>

The efficiency of a machine is a measure of the useful work done by the machine as against the work input into the machine.

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Work output of the steam engine = 225 K

Work input of the steam engine = 285 K

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Therefore, the efficiency of the steam engine is 78.9%.

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2 years ago
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No, the density of diamond and graphite would not be the same

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Since:

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artcher [175]

Answer:

(a) 92 %

(b) 6.76 %

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length, l = 4 m, height, h = 5 m, width, w = 3 m, density of water = 1000 kg/m^3

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(a) Let v be the volume of ice below water surface.

By the principle of flotation

Buoyant force = weight of ice block

Volume immersed x density of water x g = Total volume of ice block x density

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v x 1000 x g = V x 920 x g

v / V = 0.92

% of volume immersed in water = v/V x 100 = 0.92 x 100 = 92 %

(b) Let v be the volume of ice below the mercury.

By the principle of flotation

Buoyant force = weight of ice block

Volume immersed x density of mercury x g = Total volume of ice block x  

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v x 13600 x g = V x 920 x g

v / V = 0.0676

% of volume immersed in water = v/V x 100 = 0.0676 x 100 = 6.76 %

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