Question

An investor would like to invest $60,000 in 2 stocks from a list of 6 suggested by a broker. How many investments of $30,000 each are possible?

Answer 1

15 is exact answer because in combination or does not matter<span />

Answer 2

Answer:

Total 15 ways are possible to select two investments of $30,000 each.

Step-by-step explanation:

An investor would like to invest $60,000 in 2 stocks from a list of 6.

Amount of each investments is $30,000.

If we need to select r its from n items, then

$^nC_r=\frac{n!}{r!(n-r)!}$

We have to select 2 stocks from 6.

$^6C_2=\frac{6!}{2!(6-2)!}$

$^6C_2=\frac{6!}{2!4!}$

$^6C_2=\frac{6\times 5\times 4!}{2\times 1\times 4!}$

$^6C_2=15$

Therefore, total 15 ways are possible to select two investments of $30,000 each.