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Mkey [24]
3 years ago
12

Jimmy has a diecast metal car that is a scale model of an actual race car. If the actual length of the car is 10 feet 6 inches a

nd the model has a length of 7 inches, what is the scale factor of the model to the actual car?
Mathematics
1 answer:
kirill115 [55]3 years ago
8 0
The scale factor would be -8 because...

126 inches / 7 inches = 8 inches. 

Because the car is bigger than the scale, it would be a negative scale factor.
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The length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58° to 3
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<h3>Answer: Approximately 119.76 meters</h3>

===================================================

Work Shown:

x = starting length of the shadow

y = height of the pole

tan(angle) = opposite/adjacent

tan(58) = y/x

1.6003345 = y/x

1.6003345x = y

x = y/1.6003345

x = (1/1.6003345)y

x = 0.62486936y

-------------------------

When the angle changes, the adjacent side gets 90 meters longer

tan(angle) = opposite/adjacent

tan(36) = y/(x+90)

0.72654253 = y/(0.62486936y+90)

0.72654253(0.62486936y+90) = y

0.453994166y + 65.3888277 = y

65.3888277 = y-0.453994166y

65.3888277 = 0.546005834y

0.546005834y = 65.3888277

y = 65.3888277/0.546005834

y = 119.758478075162

y = 119.76

The height of the pole is about 119.76 meters.

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Answer:

The answer is 274

Step-by-step explanation:

<h3><u>Given</u>;</h3>
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<h3><u>To </u><u>Find</u>;</h3>
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Now,

Definition of Variance:

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So,

\frac{ {(87 - 78)}^{2}   +  ( {46 - 78)}^{2}   + (90 - 78) {}^{2} +  ({78 - 78)}^{2} + ( {89 - 78)}^{2}   } {5}

Var(X) \:  =   \frac{1370}{5}  = 274 \\

Thus, The variance of the sequence is 274.

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