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Semmy [17]
3 years ago
15

Determine which situation could be represented by the following system of linear equations. x+y=70 8x+5y=410 A. At the floral sh

op, Mary buys eight large bouquets and five small bouquets for a total of $410. Mark buys one large bouquet and one small bouquet for $70 less than Mary pays. B. Packs of file folders cost $8 each and boxes of pens cost $5. An office manager ordered 70 more boxes of pens than packs of file folders and paid a total of $410. C. Each student at an elementary school is required to have five notebooks and eight pencils. One grade has a total of 70 school supplies and another grade has a total of 410 school supplies. D. Evaporated milk comes in eight-ounce cans and five-ounce cans. A grocery store sold 410 ounces of evaporated milk in 70 cans.
Mathematics
1 answer:
vodka [1.7K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Because x+y=70, x=1 large bouquet and y= 1 small bouquet.

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5 0
2 years ago
The probability that Latisha orders french fries at lunch is .32 and the probability that she orders a grilled cheese and fries
EastWind [94]

There is a typo error in the last part of the question. The corrected part is-

"If the probability that she orders just a grilled cheese sandwich is .76, what is the probability that she will order a grilled cheese or fries?"

Answer:

The probability that she will order a grilled cheese sandwich or fries is <u>0.43.</u>

Step-by-step explanation:

Given:

Probability of ordering fries is, P(F)=0.32

Probability of ordering cheese sandwich is, P(S)=0.76

Probability of ordering both sandwich and fries is, P(F\cap S)=0.65

Probability of ordering cheese sandwich or fries is given by the union of both the events 'F' and 'S' given as P(F\cup S).

Now, using addition theorem of probability, we get:

P(F\cup S)=P(F)+P(S)-P(F\cap S)\\P(F\cup S)=0.32+0.76-0.65\\P(F\cup S)=0.43

Therefore, probability of ordering cheese sandwich or fries is 0.43.

8 0
3 years ago
fie abc un triunghi cu masura unghiului a de 90 de grade ab este 6 cm bc=10 si ca=8 calculati;sin b; tg b; sin c; tg c; cos b; c
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SinB = cosC = AC / BC = 8/10 = 4/5;
tgB = ctg C = AC/AB = 8/6 = 4/3, because we use T. Pitagora for calculating AB;
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tgC = ctgB = AB/ AC = 6/8 = 3/4.

6 0
3 years ago
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