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Reptile [31]
3 years ago
10

Please answer asap

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0

Answer:

(B)permits only certain substances to leave but all to enter

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find the equation of the line that is parallel to y=3x-2 and contains the point (2,11), answer all boxes please
stiks02 [169]

Answer:

y = 3x+6

Step-by-step explanation:

y=3x-2

This is in the form

y = mx+b where m is the slope and b is the y intercept

The slope is 3 so a line parallel also has a slope of 3 since parallel lines have the same slope.

Using slope intercept form

y = 3x+b

We have a point (2,11)

11 = 3*2+b

11 =6+b

11-6 = b

5 =b

The equation is

y = 3x+6

4 0
3 years ago
Solve the following system.<br> x^2 + y^2 = 25<br> 2x + y = 10<br> The solution set
tia_tia [17]
\begin{cases} x^{2}+y^{2}=25 \\ 2x+y=10 \end{cases} \\  \\ \begin{cases} x^{2}+y^{2}=25 \\ y=10 -2x\end{cases} \\  \\ \begin{cases} x^{2}+(10-2x)^{2}=25 \\y=10-2x \end{cases} \\  \\ \begin{cases} x^{2}+100-40x+4x^{2}=25 \\y=10-2x \end{cases} \\  \\ \begin{cases} 5x^{2}-40x+75=0 \\y=10-2x \end{cases}

\begin{cases} x^{2}-8x+15=0 \\y=10-2x \end{cases} \\  \\  \begin{cases} \Delta=(-8)^{2}-4*1*15=64-60=4; \ \ \  \sqrt{\Delta} =2 \\y=10-2x \end{cases} \\  \\  \begin{cases} x_{1}= \frac{8-2}{2} =3 \ \wedge \ x_{2}= \frac{8+2}{2}=5  \\y=10-2*3=4 \ \wedge \ y=10-2*5=0 \end{cases}
4 0
3 years ago
Does anyone know how to do this ​
Ne4ueva [31]

Answer:

y = 1

Step-by-step explanation:

4 - (y-3) = 3(y+1) - 4(1 - y)

4 -y +3 = 3y + 3 - 4 + 4y

7 - y = 7y - 1

7 + 1 = 7y + y

8 = 8y

8/8 = y

4 0
3 years ago
How do you write the sum of one-sixth of n and one-fifth of g
kati45 [8]

Answer: \frac{n}{6}+\frac{g}{5}

Step-by-step explanation:

One-sixth of n is n/6.

One-fifth of g is g/5.

The sum means to add, so the expression is \frac{n}{6}+\frac{g}{5}.

8 0
2 years ago
Factor the following equation to find its zeros. y = x² - 36
alukav5142 [94]

Answer:

x = 6, x = - 6

Step-by-step explanation:

Given

y = x² - 36

To find the zeros let y = 0, that is

x² - 36 = 0 ← x² - 36 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b), thus

x² - 36 = 0

x² - 6² = 0

(x - 6)(x + 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 6 = 0 ⇒ x = - 6

3 0
3 years ago
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