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natita [175]
3 years ago
14

Ginny’s favorite cookie recipe requires 1 1/2 cups of sugar to make 24 cookies. How much sugar does Ginny need to make 36 of the

se cookies
Mathematics
1 answer:
Delicious77 [7]3 years ago
7 0

Ginny needs 2\frac{1}{4} cups of sugar to make 36 cookies.

Step-by-step explanation:

Given,

Sugar cups required for 24 cookies = 1\frac{1}{2}=\frac{3}{2}\ cups

Ratio of sugar cups to cookies = \frac{3}{2}:24

Let,

x be the number of cups needed for 36 cookies.

Ratio of sugar cups to cookies = x:36\\

Using proportion;

Ratio of sugar cups to cookies :: Ratio of sugar cups to cookies

\frac{3}{2}:24::x:36

Product of mean = Product of extreme

24*x=\frac{3}{2}*36\\24x=54

Dividing both sides by 24

\frac{24x}{24}=\frac{54}{24}\\x=\frac{9}{4}\\x=2\frac{1}{4}

Ginny needs 2\frac{1}{4} cups of sugar to make 36 cookies.

Keywords: fraction, proportion

Learn more about fractions at:

  • brainly.com/question/96882
  • brainly.com/question/96535

#LearnwithBrainly

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Como identifico una X Cubica en un polinomio
Nadya [2.5K]

la componente "cubica" será aquella que tenga un exponente igual a 3.

<h3>¿como identifico una X Cubica en un polinomio?</h3>

Un polinomio tiene la forma general:

p(x) = a_n*x^n + ... + a_1*x^1 + a_0

Donde todos los exponentes de x son numeros naturales.

Particularmente, la componente "cubica" será aquella que tenga un exponente igual a 3.

Entonces, por ejemplo, en:

p(x) = 4*x^5 + 2*x^4 + 5*x^3

La parte cubica será:

5*x^3

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brainly.com/question/4142886

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8 0
2 years ago
The kittens, Annie and Josie, are pushing a ball, Annie with a force magnitude of 80 N in a direction of 133 degrees, and Josie
kvv77 [185]

Answer: Then the magnitude of the force is 37.86N, and the direction is 54.35°

Step-by-step explanation:

We can write the forces as vectors.

We know that Annie pushes with a magnitude of 80N in a direction of 133° (Remember that the angles are always measured from the x-axis)

The components of this force, (Ax, Ay), are then:

Ax = 80N*cos(133°)

Ay = 80N*sin(133°)

And we know that Josie pushes with a magnitude of 95N in direction of 290°

The components of this force, (Jx, Jy), are:

Jx = 95N*cos(290°)

Jy = 95N*sin(290°)

When we add these forces, the total force acting on the ball is:

F = (80N*cos(133°) ,  80N*sin(133°)) + (95N*cos(290°), 95N*sin(290°))

F = (80N*cos(133°) + 95N*cos(290°), 80N*sin(133°) + 95N*sin(290°))

Now, the third kitten wants to do a force K, in a direction θ, such that the net force acting on the ball is zero.

Then we must have that, each component of the force of the third cat (K*cos(θ)  on the x-axis and k*sin(θ) on the y-axis), is such that:

K*cos(θ) + 80N*cos(133°) + 95N*cos(290°) = 0

k*sin(θ)  + 80N*sin(133°) + 95N*sin(290°) = 0

Now we need to solve that system for k and θ

if we simplify the equations we get:

k*cos(θ) - 22.07N = 0

k*sin(θ)  -30.76N  = 0

Now we can rewrite them as:

k*cos(θ) = 22.07N

k*sin(θ)   = 30.76N  

Now we can take the quotiet between both equations to get:

(k*sin(θ))/(k*cos(θ)) = 30.76N/22.07N

Tan(θ) = 1.394

θ = Atan(1.394) = 54.35°

Now that we know the angle, we can find the value of the magnitude k, by using one of the two equations of the system:

k*cos(54.35°) = 22.07N

k = 22.07N/cos(54.35°) = 37.86N

Then the magnitude of this force is 37.86N, and the direction is 54.35°

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2 years ago
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timofeeve [1]

Answer:

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3 years ago
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iVinArrow [24]

Answer: 0.25g<2.50.... g<10

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