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Yuliya22 [10]
3 years ago
15

Show me how you solve it

Mathematics
1 answer:
julia-pushkina [17]3 years ago
7 0

Answer:

5^20

Step-by-step explanation:

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u>

\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n} }

Therefore:

\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{8 - 3})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{5})^{4}  }

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u><u>I</u>

\displaystyle \large{( {a}^{m} ) ^{n} =  {a}^{m \times n}  }

Thus:

\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{8 - 3})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{5})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  = {5}^{5 \times 4}   } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =   {5}^{20} }

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Answer:


Step-by-step explanation:

First we can determine the x value of our vertex via the equation:

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Note that in general a quadratic equation is such that:

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Therefore we can determine the x component of the vertex by plugging in the values known and so:

x=\frac{-b}{2a}=\frac{-6}{2(1)}=\frac{-6}{2}=-3

Now we can determine the y-component of our vertex by plugging in the x-component to the equation and so:

f(x)=x^2+6x+13\\\\f(-3)=(-3)^2+6(-3)+13\\\\f(-3)=4

Therefore our vertex is (-3,4).  Now in vertex our x component determines is the axis of symmetry so the equation for axis of symmetry is:

x=-3

Similarly, the y-component of our vertex is the minimum or maximum.  In this case it is the minimum you can determine this because a is positive meaning that the parabola will point up, and so the equation for the  minimum is:

y=4

The range of the formula is the smallest y-value meaning the minimum y=4 and all real numbers that are more than 4, mathematically:

Range = All real numbers greater than or equal to 4.

4 0
4 years ago
WHATS THE ANSWER ILL GIVE BRAINLIEST.
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Step-by-step explanation:

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Step-by-step explanation:

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<h2>Explanation:</h2>

Here we have the following expression:

(csc x - 1) (csc x + 1)

So we need to extend this. Remember that the difference of squares tells us:

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So here:

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Thus:

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