The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
Answer:
Option B You are on part of Earth that is in the umbra of the moon’s shadow
Explanation:
Solar eclipses are observable in the shadow zone created by the Moon's occultation of the Sun. In the case of a total eclipse and only in this one, the shadow zone where it is possible to observe this phenomenon of total eclipse is called “path of totality“.
Answer:
The insulin must be administered.
Explanation:
In the given question the Mary has the acidosis that is the level of pH in the blood have dropped below 7.
It is also provided that the smell of her breath is fruity due to the accumulation of fruity smell molecules called ketones which could be the result of the ketosis. Ketosis occurs when the cellular respiration uses fat as a substrate instead of the carbohydrate. This shows Mary has a condition called ketoacidosis.
The increased level of the glucose in the blood shows that the glucose is not absorbed by the cell which involves the insulin therefore the doctor should administer the insulin drug to the patient.
Thus, insulin is the correct answer.
The regulatory genes are not part of the lac operon.
