The answer to the problem is B.2
Answer:
The circumcenter is (-17/2, -15/2)
Step-by-step explanation:
To find the circumcenter, solve any two bisector equations and find out the intersection points. The given are A(1,1), B(0,2), and C(3,-2).Midpoint of AB = (1/2, 3/2) - You can get the midpoint by getting the average of x-coordinates and y-coordinates. Slope of AB = -1Slope of perpendicular bisector = 1Equation of AB with slope 1 and the coordinates (1/2, 3/2) isy - (3/2) = (1)(x - 1/2) y = x+1Do the same for ACMidpoint of AC = (2, -1/2)Slope of AC = -3/2Slope of perpendicular bisector = 2/3Equation of AC with slope 2/3 and the coordinates (2, -1/2) isy - (-1/2) = (2/3)(x - 2) y = -11/6 + 2x/3So the perpendicular bisectors of AB and BC meety = x+1y = -11/6 + 2x/3To solve for x,(-11/6 + 2x/3) = (x+1)x= -17/2Now get y by substituting y = (-17/2) + 1y = -15/2
The length of the curved surface is the circumfrence of a circle with radius r = 10/2 = 5 decimeters.
Length of curved surface = 2π x 5 = 10π ≈ 31.4 decimeters.
12
You want to find an equivalent ratio with 2:3. As the question already gives you 8 where 2 used to be, you need to find out what change occurred to get from 2 to 8 (a multiplication of 4). To find the missing part of the ratio, multiply 4 with 3 to get 12.
The opposite way that the normal y=x would be!
