SOMEONE PLEASE HELP IVE BEEN STUCK ON THIS SO LONG AND I DONT KNOW WHAT TO WRITE PLEASE HELP ITS DUE TODAY!!!:(

Mathematics

1 answer:

Bess [88]2 years ago

7 0

Answer:

EXPRESSION: $t\geq 11$

Step-by-step explanation:

That equation is telling you that t should be equal to or greater than 11

amount of players:

$4t\geq 44$

11 (minimum) times 4 teams = 44

44 = minimum amount of people playing in competition.

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Point x is located at (-2,-6) and point z is located at (0,5). Find the y value for the point y that is located 1/5 the disteanc

Sedaia [141]

Answer:

-3 1/2

Step-by-step explanation:

We have to find the distance between x and z along the y-axis.

This will be: 5 - -6 = 11 units

1/5 of 11 = 1/5 × 11

= 11/5

= 2 1/5

Now add 2.5 to -6

2 1/2 + -6 = -3 1/2

The value of y = -3 1/2

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3 years ago

A regular hexagonal prism has an edge length 12 cm, and height 10 cm. Identify the volume of the prism to the nearest tenth.

Alexeev081 [22]

Check the picture below.

so the volume will simply be the area of the hexagonal face times the height.

$\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\stackrel{\qquad degrees}{\cot\left( \frac{180}{n} \right)}~~ \begin{cases} n=\stackrel{number~of}{sides}\\ s=\stackrel{length~of}{side}\\[-0.5em] \hrulefill\\ n=6\\ s=12 \end{cases}\implies A=\cfrac{1}{4}(6)(12)^2\cot\left( \frac{180}{6} \right) \\\\\\ A=216\cot(30^o)\implies A=216\sqrt{3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the hexagon}}{(216\sqrt{3})}~~\stackrel{height}{(10)}\implies 2160\sqrt{3}~~\approx ~~3741.2~cm^3$

6 0

1 year ago

A telephone company charges a fixed monthly rate plus a rate per minute of usage. The company charges $155 for 100 minutes of us

torisob [31]

Answer:

The answer is D.

Step-by-step explanation:

As said in the problem, we are labeling the total minutes used <em>x </em>and the total monthly income as <em>y</em>. This means that in the graph we will be making the y-axis should represent the total monthly charges, and the x-axis should represent the total minutes.

Thus the graph should go through points (100,155) and (200,245) and its slope is:

$\frac{245-155}{200-100} =0.9.$