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Valentin [98]
3 years ago
8

What's X in 2x+4=9+xPLEASE EXPLAIN​

Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer:

The answer is x = 5

Step-by-step explanation:

So we have to equation 2x + 4 = 9 + x.

2x + 4 = 9 + x

Subtract x to both sides of the equation (to get rid of the +x on the right side of the equation)

2x + 4 - x = 9 + x -x

Simplify

x + 4 = 9

Subtract 4 from both sides of the equation (to get rid of the +4 on the left side of the equation)

x + 4 - 4 = 9 - 4

Simplify

x = 5

The answer is x = 5

I hope you find my answer helpful. If anything in my answer confuses you, feel free to ask me questions. Happy studying. :)

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A certain restaurant offers 6 kinds of cheese and 2 kinds of fruit for its dessert platter. If each dessert platter contains an
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<h3>27 different dessert platters can be offered by restaurant</h3>

<em><u>Solution:</u></em>

Given that,

A certain restaurant offers 6 kinds of cheese and 2 kinds of fruit for its dessert platter

Each dessert platter contains an equal number of kinds of cheese and kinds of fruit

<em><u>For this problem there are two scenarios: </u></em>

1 ) one cheese and one fruit

2 ) two cheese and two fruit

<em><u>For one cheese and one fruit</u></em>

<em><u></u></em>6C_1 \times 2C_1

Use the combination formula

C(n, r) = \frac{n !}{r ! (n-r) ! }

Where, n is total items and r is the items being chosen at a time

6C_1 \times 2C_1 = \frac{ 6 ! }{ 1 ! (6 - 1) ! } \times \frac{ 2 ! }{ 1 ! ( 2 -1 ) ! }\\\\6C_1 \times 2C_1 = \frac{ 6 ! }{ 1 ! 5 ! } \times \frac{ 2 ! }{ 1 ! 1 ! }\\\\6C_1 \times 2C_1 = \frac{ 6 \times 5 \times 4 \times 3 \times 2 \times 1}{ 5 \times 4 \times 3 \times 2 \times 1} \times 2 \times 1\\\\6C_1 \times 2C_1 = 6 \times 2 = 12

<em><u>For 2 cheese and 2 fruits</u></em>

6C_2 \times 2C_2

6C_2 \times 2C_2 = \frac{ 6 ! }{ 2 ! ( 6 - 2) ! } \times 2C_2\\\\We\ know\ that\ 2C_2 = 1\\\\6C_2 \times 2C_2 = \frac{ 6 ! }{ 2 ! ( 6 - 2) ! } \times  1\\\\6C_2 \times 2C_2 = \frac{ 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{2 \times 1 \times 4 \times 3 \times 2 \times 1 }\\\\6C_2 \times 2C_2 = 15

So, total ways = 12 + 15 = 27

Thus, 27 different dessert platters can be offered by restaurant

5 0
4 years ago
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