Looks like a pretty regular system, no parallel lines. In fact the second equation is a vertical line as written; not sure if that's a typo. Either way,
Answer: EXACTLY ONE SOLUTION
Answer:
![m=4\frac{1}{3}](https://tex.z-dn.net/?f=m%3D4%5Cfrac%7B1%7D%7B3%7D)
Step-by-step explanation:
the equation to this is
![y=4\frac{1}{3}x](https://tex.z-dn.net/?f=y%3D4%5Cfrac%7B1%7D%7B3%7Dx)
and slop-intercept form is
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
with m being the slope,
so,
![m=4\frac{1}{3}](https://tex.z-dn.net/?f=m%3D4%5Cfrac%7B1%7D%7B3%7D)
Given:
![\text{ Dimension = 3}\times5](https://tex.z-dn.net/?f=%5Ctext%7B%20Dimension%20%3D%203%7D%5Ctimes5)
Sol:
Area of picture is:
![\begin{gathered} =\text{ length}\times\text{ Width} \\ \\ =15 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%3D%5Ctext%7B%20length%7D%5Ctimes%5Ctext%7B%20Width%7D%20%5C%5C%20%20%5C%5C%20%3D15%20%5Cend%7Bgathered%7D)
If the cost $10 per square inch then price of 15 square inch is:
![\begin{gathered} =15\times10 \\ \\ =150 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%3D15%5Ctimes10%20%5C%5C%20%20%5C%5C%20%3D150%20%5Cend%7Bgathered%7D)
If the quadruple of dimension that mean:
![\begin{gathered} \text{ l ength = 4 length} \\ \\ Width\text{ = 4 width} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7B%20l%20ength%20%3D%204%20length%7D%20%5C%5C%20%20%5C%5C%20Width%5Ctext%7B%20%3D%204%20width%7D%20%5Cend%7Bgathered%7D)
So area is:
![\begin{gathered} A=4\text{ length}\times4\text{ Width} \\ \\ A=4(15) \\ \\ A=60 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D4%5Ctext%7B%20length%7D%5Ctimes4%5Ctext%7B%20Width%7D%20%5C%5C%20%20%5C%5C%20A%3D4%2815%29%20%5C%5C%20%20%5C%5C%20A%3D60%20%5Cend%7Bgathered%7D)
So price is:
tan( tehta ) = 2/3
Sin( tetha ) = 2/√13
tan( tetha ) + Sin( tetha ) = 2/3 + 2/√13
= 2√13 + 6 / 3√13
-9a + 11ad - 35a + ad = -44a + 12ad
hope this helps