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lara [203]
3 years ago
12

Linda is training to become a certified network design expert and consultant. While researching about the process of cellular ra

dio transmissions, Linda learns that when a cell phone user begins to make a call, it is picked up by the cell tower located in the cell in which the cell phone is located and that belongs to the user's wireless provider. Which of the following is the next step in this process?
a. The cell tower forwards the call to the wireless provider's Mobile Telephone Switching Office
b. The cell tower requests the cell phone user to stay in the current location until the recipient answers the call.
c. The cell tower routes the call to the sender's telephone via his or her mobile or conventional telephone service provider.
d. The cell tower combines service areas into overlapping bevel-shaped zones called frames.
Computers and Technology
1 answer:
mel-nik [20]3 years ago
8 0

Answer:

a. The cell tower forwards the call to the wireless provider's Mobile Telephone Switching Office

Explanation:

When a cell phone user begins to make a call, it is picked up by the cell tower located in the cell in which the cell phone is located and that belongs to the user's wireless provider. The next step in this process is that the cell tower forwards the call to the wireless provider's Mobile Telephone Switching Office.

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Please, give me a comic or story idea. I will mark brainliest. ( i need 5 slides with 2 characters in the story or comic) Please
salantis [7]

Answer:

Jack and John

Explanation:

Jack called John and offered him to come with him and some other friends to go out to the mall.

.....

8 0
3 years ago
Read 2 more answers
In the following code segment, assume that the ArrayList numList has been properly declared and initialized to contain the Integ
KATRIN_1 [288]

Answer:

e. 4

Explanation:

The code segment will not work as intended if the value of the variable val is 4. This is because the while loop is comparing the value of the variable val to the value of each element within the numList. Since there is no element that is bigger than or equal to the number 4, this means that if the variable val is given the value of 4 it will become an infinite loop. This would cause the program to crash and not work as intended.

8 0
3 years ago
(14 points) Consider the Matrix, M = 16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1 . Using the index operations write MATLAB statements
Sonja [21]

Answer:

The Matlab commands for the given index operations and corresponding outputs are given below.

Explanation:

clc   % is used to clear the command window of the Matlab

clear all   % is used to clear the variables stored in Matlab workspace

% We are given a 4x4 matrix

Matlab command:

M = [16 2 3 13; 5 11 10 8; 9 7 6 12; 4 14 15 1]

output:

M =

   16     2     3    13

    5    11    10     8

    9     7     6    12

    4    14    15     1

(a) The value in the first row and second column (ie. 2)

Matlab command:

a = M(1,2)

% where a = Matrix(row_1,column_2)

output:

a =

    2

(b) The value in the third row and third column (ie. 6)

Matlab command:

b = M(3,3)

% where b = Matrix(row_3,column_3)

output:

b =

     6  

(c) All the elements in the first row

Matlab command:

c = M(1,:)

% where c = Matrix(row_1,:)

output:

c =

   16     2     3    13

(d) All the elements in the second column

Matlab command:

d = M(:,2)

% where d = Matrix(:,column_2)

output:

d =

    2

   11

    7

   14

(e) All the elements in the first 2 rows (row 1 & 2)

Matlab command:

e = M([1,2],:)

% where e = Matrix([row_1,row_2],:)

output:

e =

   16     2     3    13

    5    11    10     8  

(f) All the elements in the last 2 columns (columns 3 & 4)

Matlab command:

f = M(:,[3,4])

% where f= Matrix(:,[column_3,column_4])

output:

f =  

    3    13

   10     8

    6    12

   15     1

(g) The elements 3 13 10 8

Matlab command:

g = [M(1,3) M(1,4); M(2,3) M(2,4)]

% where g = Matrix(row_1,column_3) M(row_1,column_4); M(row_2,column_3), M(row_2,column_4)

output:

g =

    3    13

   10     8

8 0
3 years ago
Below is a list of 32-bit memory address references, given as word addresses.
Maru [420]

For a direct mapped cache the general rule is: first figure out the bits of the offset (the right-most bits of the address), then figure out the bits of the index (the next-to right-most address bits), and then the tag is everything left over (on the left side).

One way to think of a direct mapped cache is as a table with rows and columns. The index tells you what row to look at, then you compare the tag for that row, and if it matches, the offsettells you which column to use. (Note that the order you use the parts: index/tag/offset, is different than the order in which you figure out which bits are which: offset/index/tag.)

So in part (a) The block size is 1 word, so you need 0 offset bits (because <span><span><span>20</span>=1</span><span><span>20</span>=1</span></span>). You have 16 blocks, so you need 4 index bits to give 16 different indices (because <span><span><span>24</span>=16</span><span><span>24</span>=16</span></span>). That leaves you with the remaining 28 bits for the tag. You seem to have gotten this mostly right (except for the rows for "180" and "43" where you seem to have missed a few bits, and the row for "181" where you interchanged some bits when converting to binary, I think). You are correct that everything is a miss.

For part (b) The block size is 2 words, so you need 1 offset bit (because <span><span><span>21</span>=2</span><span><span>21</span>=2</span></span>). You have 8 blocks, so you need 3 index bits to give 8 different row indices (because <span><span><span>23</span>=8</span><span><span>23</span>=8</span></span>). That leaves you with the remaining 28 bits for the tag. Again you got it mostly right except for the rows for "180" and "43" and "181". (Which then will change some of the hits and misses.)

5 0
3 years ago
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Yuki888 [10]
I think it's to make sure no plagerise 
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