Answer:
B
Explanation:
This feels like an error on the question issuer's part.
import java.util.Scanner;
public class JavaApplication70 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Input a String:");
String txt = scan.nextLine();
System.out.println("Input an integer:");
int num = scan.nextInt();
String newTxt = "";
int w = 0;
for (int i = txt.length()-1; i >= 0; i--){
char c = txt.charAt(i);
while (w < num){
newTxt += c;
w++;
}
w = 0;
}
System.out.println(newTxt);
}
}
I hope this helps!
In the case above, the cell that you can highlight before selecting freeze panes is row 3 column 4.
<h3>How do one freeze several column?</h3>
This can be done when a person select the column that's is said to be next to the right of the last column a person want to freeze.
Therefore, In the case above, the cell that you can highlight before selecting freeze panes is row 3 column 4.
Learn more about panes from
brainly.com/question/17194167
#SPJ1
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