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hjlf
3 years ago
13

Does a bathtub hold more than 20 liters​

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Yes. A bathtub could hold at least 24 liters. Depending on the size of the tub.

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9. enter the value for x that makes the equation 5+3x-37=6x+23-8x true ?
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A linear set of points with a unique starting point and extending infinitely in one direction what term matches the definition?
bija089 [108]

Answer:- Option A "ray" is the right term which matches with the definition.


Explanation:-

A ray is a line that has one fixed endpoint, and extends infinitely along the line from the fixed endpoint.

Therefore, the term which matches with the given definition is "ray".

Thus A linear set of points with a unique starting point and extending infinitely in one direction is called a ray.


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59.5

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2 years ago
Arnold is studying data and statistics in math class. His teacher has assigned a project, where the students must develop a rese
Tatiana [17]

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Step-by-step explanation:

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ASAP!!! Use the pythagorean theorem to prove that the point (√2/2, √2/2) lies on the unit circle. I need setup, explination, ans
docker41 [41]

Answer:

In brief, apply the pythagorean theorem to show that the distance between the point (\sqrt{2}/2,\sqrt{2}/2) and the origin is 1.

Step-by-step explanation:

The pythagorean theorem can give the distance between two points on a plane if their coordinates are known.

A point is on a circle if its distance from the center of the circle is the same as the radius of the circle.

On a cartesian plane, the unit circle is a circle  

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Therefore, to show that the point (\sqrt{2}/2,\sqrt{2}/2) is on the unit circle, show that the distance between (\sqrt{2}/2,\sqrt{2}/2) and (0,0) equals to 1.

What's the distance between (\sqrt{2}/2,\sqrt{2}/2) and (0,0)?

\displaystyle \sqrt{\left(\frac{\sqrt{2}}{2}-0}\right)^{2} + \left(\frac{\sqrt{2}}{2}-0\right)^{2}} = \sqrt{\frac{1}{2} + \frac{1}{2}}= \sqrt{1}= 1.

By the pythagorean theorem, the distance between (\sqrt{2}/2,\sqrt{2}/2) and the center of the unit circle, (0,0), is the same as the radius of the unit circle, 1. As a result, the point (\sqrt{2}/2,\sqrt{2}/2) is on the unit circle.

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3 years ago
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