Let's assign three blanks for each digit of the unknown number. But let's fill in the tens digit because it is already specified.
_ 4 _
The last digit should be even to make it even. The possible digits for this are 2, 4, 6, and 8. The first digit could be any digit from 1 to 9. Therefore, the possible answers are
142 242 342 442 542 642 742 842 942
144 244 344 444 544 644 744 844 944
146 246 346 446 546 646 746 846 946
148 248 348 448 548 648 748 848 948
Therefore, there are a total of 36 possible answers.
Answer:
it should be |8| or just 8 because there can not be a negative in the absolute value sign. pretty sure but not 100%
Answer: 15/91 which is choice B
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There are two methods to find this answer.
Method 1) We have 6 girls and 8+6 = 14 students. The probability of picking a girl is 6/14 = 3/7. After the first girl is chosen, we have 5 girls left out of 14-1 = 13 students overall. The probability of picking another girl (assuming the first selection was a girl) is 5/13. Multiply these probabilities: (3/7)*(5/13) = (3*5)/(7*13) = 15/91
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Method 2) We can use the nCr combination formula. Order does not matter.
We have nCr = 6 C 2 = 15 ways to pick 2 girls. See the attached image below for the steps (figure 1)
Out of nCr = 14 C 2 = 91 ways to pick 2 students. See the attached image below for the steps (figure 2)
So that's another way to get the answer 15/91.
Answer:
d. ![x = 10](https://tex.z-dn.net/?f=x%20%3D%2010)
e. ![x=\sqrt[3]{\dfrac{15}{4}}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B15%7D%7B4%7D%7D)
Step-by-step explanation:
I've typed up my workings in MS Word and attached them (as it's very difficult to type this in the Brainly equation editor).
I've used the product, quotient and power log laws.
Product: ![log_a(x)+log_a(y)=log_a(xy)](https://tex.z-dn.net/?f=log_a%28x%29%2Blog_a%28y%29%3Dlog_a%28xy%29)
Quotient: ![log_a(x)-log_a(y)=log_a(\dfrac{x}{y})](https://tex.z-dn.net/?f=log_a%28x%29-log_a%28y%29%3Dlog_a%28%5Cdfrac%7Bx%7D%7By%7D%29)
Power: ![p\log_a(x)=log_a(x^p)](https://tex.z-dn.net/?f=p%5Clog_a%28x%29%3Dlog_a%28x%5Ep%29)