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Nady [450]
2 years ago
9

Searches related to In 1997 there were 43.2 who used free weights increases 6% annually, write an equation for the number of peo

ple using free weights t year 1997?
Mathematics
1 answer:
klasskru [66]2 years ago
6 0

Answer:

P(t)=43.2(1.06)^t

Step-by-step explanation:

We have been given that searches related in 1997 there were 43.2 who used free weights increases 6% annually. We are asked to write an equation for the number of people using free weights t year after 1997.

Let t=0 represent year 1997.

We will use exponential growth formula to write our given function.

y=a\cdot (1+r)^x, where,

y = Final value,

a = Initial value,

r = Growth rate in decimal form,

x = time.

Let us convert 6% into decimal form.

6\%=\frac{6}{100}=0.06

Initially there were 43.2 who used free weights, so initial value is 43.2.

Upon substituting our given values in exponential growth formula, we will get:

P(t)=43.2(1+0.06)^t

P(t)=43.2(1.06)^t

Therefore, our required equation would be P(t)=43.2(1.06)^t.

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Thulani goes to the library every 7 days. He goes to the market every 4 days
emmasim [6.3K]

Thulani goes to both the library and the market for 5 more times during the year.

Step-by-step explanation:

Thulani goes to the library every 7 days. He goes to the market every 4 days.

We have to calculate the Least Common Multiple (LCM) to analyze the next common day on which he will go to both places.

The factors of 7 are:  1 x 7

The factors of 4 are: 2 x 2

Therefore, the LCM would be = 1 x 7 x 2 x 2

LCM = 28

LCM indicates that Thulani will go to both places on every 28th day.

To calculate the number of times (n) he will go to both places on same day. We can use the formula mentioned below:'

n = \frac{Number of days}{frequency}

Here frequency represents the LCM = 28.

The number of days are:

August: 30 (we are excluding 1st August)

September: 30

October: 31

November: 30

December: 31

Total  = 152

By putting the values in formula, we get

n = \frac{152}{28}

n = 5.42

As, the number of times can only be a whole number. Therefore, Thulani goes to both the library and the market for 5 more times during the year.

Learn more:

The following links have more information

brainly.com/question/12419898

brainly.com/question/12764620

Keywords: LCM, same day

#learnwithBrainly

7 0
3 years ago
If you buy a new computer printer for $260 and the sales tax is 4.5%, how much will you pay in sales tax?
solniwko [45]

Answer:

Okay, so i'm pretty sure it's $11.70 (A)

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A boat heading out to sea starts out at Point A, at a horizontal distance of 804 feet from a lighthouse/the shore. From that poi
marishachu [46]

Answer: 672 feets

Step-by-step explanation:

Using the solution diagram attached, the vertical height, h of the lighthouse ;

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 2 = h / 804

h = tan 2 * 804

h = 28.076 feets

Using h, we can obtain the distance CB :

Tan θ = opposite / Adjacent

Tan 2 = 28.076 / CB

CB = 28.076 / Tan 12°

CB = 132.08860 feets

Distance between A and B

804 - 132.08860

= 671.9 feets

6 0
2 years ago
Liquid A has a density of 0.7g/cm^3
TiliK225 [7]
\rho = \frac{m}{V} \Rightarrow V=\frac{m}{\rho}
ρ - density, m - mass, V - volume

Liquid A:
\rho=0.7 \ \frac{g}{cm^3} \\
m=140 \ g \\
\\ V=\frac{140 \ g}{0.7 \ \frac{g}{cm^3}}=200 \ cm^3

Liquid B:
\rho=1.6 \ \frac{g}{cm^3} \\
m=128 \ g \\
\\ V=\frac{128 \ g}{1.6 \ \frac{g}{cm^3}}=80 \ cm^3

Liquid C:
m=140 \ g + 128 \ g=268 \ g \\
V=200 \ cm^3 + 80 \ cm^3=280 \ cm^3 \\ \\
\rho=\frac{268 \ g}{280 \ cm^3} \approx 0.96 \ \frac{g}{cm^3}

The density of liquid C is approximately 0.96 g/cm³.
5 0
3 years ago
Read 2 more answers
Solve the following equation algebraically: 5x^2=60
aalyn [17]
5x^2=60
(5x^2=60)/5
x^2=12
√(x^2)=√12

x=+/-√12
5 0
3 years ago
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