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Rainbow [258]
2 years ago
8

Can someone plsssssss check my last geometry question Pleaseeeeeee

Mathematics
1 answer:
larisa [96]2 years ago
3 0

Answer: 24

Step-by-step explanation: Segment CP equals half of what segment JC equals, so in order to find the length of JP, you need to multiply CP by 2, then add 8.

8(2)= 16

16+8 = 24

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Brigitte is shorter than 5 feet. (Brigitte's height=h). Help please
KonstantinChe [14]

Brigitte is shorter than 5 feet. (Brigitte's height=h)

We write this in  inequality form

Brigitte's height is h

So 'h' is shorter than 5 feet

Shorter means less than so we use < symbol. We should not use = symbol because height is shorter than 5 not equal to 5.

Suppose if it is given ' height is more than 5 feet ' then we use greater than symbol (>)

h is less than 5 feet

h < 5

Inequality is h < 5

3 0
2 years ago
Read 2 more answers
PLEASE HELP ILL GIVE YOU
alexdok [17]

Answer: No she cannot cover it

Step-by-step explanation:

1yd² = 1296in²

16 x 11 x 9 = 1584in²

1296in² < 1584in²

7 0
2 years ago
Describe in detail how you would plot the value 2 3/8 on a number line
malfutka [58]
Between 2 and 3, after the 2 1/4 point, but before the halfway point.
5 0
3 years ago
Confused on factoring
Dmitriy789 [7]

Answer:

The answer I got was 16

16(y^2+4x^6)(y+2x^3)(y-2x^3)

Step-by-step explanation:

3 0
3 years ago
A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack
adelina 88 [10]

OPTIONS:

A. The interquartile range of the trail mix data is greater than the range of the cracker data.

B. The value 70 is an outlier in the trail mix data.

C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.

D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

D.

Step-by-step explanation:

With the given information about how the box plot looks like, let's examine each option to see if they are true or not.

<u><em>Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."</em></u>

The interquartile range of trail mix data = 105 - 90 = 15

Range of cracker data = 100 - 70 = 30

Option A is NOT TRUE.

<u><em>Option B: "The value 70 is an outlier in the trail mix data.</em></u>"

This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.

<em><u>Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."</u></em>

Upper quartile of the trail mix data = 105

Max value of cracker data = 100

This statement is NOT TRUE.

<em><u>Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."</u></em>

The greater the range value, the greater the variation. Thus,

Range value of the trail mix data = 115 - 70 = 45

Range value of the cracker data = 100 - 70 = 30

This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.

6 0
3 years ago
Read 2 more answers
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