Solution:
Given: zj = 3- j2, zz = - 4 + j3
Part a:
zj = 3- j2 = 
zz = - 4 + j3 = 
Part b:
|zj| = |3− j2| = √3² +(−2)² = √13 = 3.60
|z1| = √(3− j2)(3+ j2) = √
13 = 3.60.
Part c:
With the help of part a:
z1z2 = 
Answer:
Slope of the perpendicular line: 2/3
Step-by-step explanation:
-2y = 3x - 6
y = - 3/2x - - 6/2
y = -3/2 + 3
$1.14 1.40 x 0.8=1.12 1.4+ 1.12=1.52 * 0.25 = 1.14
The value of the probability P(A and B) is 0.20
<h3>How to determine the
probability?</h3>
The given parameters about the probability are
P(A or B) = 0.9
P(A) = 0.5
P(B) = 0.6
To calculate the probability P(A and B), we use the following formula
P(A and B) = P(A) + P(B) - P(A or B)
Substitute the known values in the above equation
P(A and B) = 0.5 + 0.6 - 0.9
Evaluate the expression
P(A and B) = 0.2
Hence, the value of the probability P(A and B) is 0.20
Read more about probability at
brainly.com/question/25870256
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