Answer:
The value of a₁₀ is -1352
Step-by-step explanation:
a₂ = -8
a₅ = -512
Now,
a₂ = -8 can be written as
a + d = -8 ...(1) and
a₅ = -512 can be written as
a + 4d = -512 ...(2)
Now, from equation (2) we get,
a + 4d = - 512
a + d + 3d = - 512
(-8) + 3d = - 512 (.°. <u>a + d = </u><u>-8</u><u>)</u>
3d = - 512 + 8
3d = - 504
d = - 504 ÷ 3
d = - 168
Now, for the value of a put the value of d = -168 in equation (1)
a + d = -8
a + (-168) = -8
a - 168 = -8
a = 168 - 8
a = 160
Now, For a₁₀
a₁₀ = a + 9d
a₁₀ = 160 + 9(-168)
a₁₀ = 160 - 1512
a₁₀ = -1352
Thus, The value of a₁₀ is -1352
<u>-TheUnknownScientist</u>
Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
I believe the answer is (-1,1) . The origin is the same as (0, 0) so I drew the line on a quick graph and if you are talking about distance, then the answer should be correct.
Hope this helped :)
If you are solving for x than the answer would be x=4.
