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vovikov84 [41]
3 years ago
15

What theorem has been proven here?

Mathematics
1 answer:
kipiarov [429]3 years ago
6 0

Answer:

B

Step-by-step explanation:

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----------------------

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You are paid $8.25/hour. You work 35 hours/week for 3 weeks. Your involuntary deductions are FICA (7.65%), federal withholding (
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According to the Labor Department, the average duration of unemployment for adults ages 20 to 24 was 34.6 weeks during a recent
Misha Larkins [42]

Answer:

0.9173 = 91.73% probability that the average duration of unemployment was between 30 and 37 weeks.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 34.6, standard deviation of 10.2

This means that \mu = 34.6, \sigma = 10.2

Sample of 36

This means that n = 36, s = \frac{10.2}{\sqrt{36}} = 1.7

What is the probability that the average duration of unemployment was between 30 and 37 weeks?

This is the pvalue of Z when X = 37 subtracted by the pvalue of Z when X = 30.

X = 37

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{37 - 34.6}{1.7}

Z = 1.41

Z = 1.41 has a pvalue of 0.9207

X = 30

Z = \frac{X - \mu}{s}

Z = \frac{30 - 34.6}{1.7}

Z = -2.71

Z = -2.71 has a pvalue of 0.0034

0.9207 - 0.0034 = 0.9173

0.9173 = 91.73% probability that the average duration of unemployment was between 30 and 37 weeks.

7 0
2 years ago
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