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3 years ago

Perbandingan kelereng Faiz dan Bayu 4 : 11. Jumlah kelereng mereka 60 buah. Selisih kelereng keduanya adalah

Mathematics

1 answer:

stepladder [879]3 years ago

3 0

Answer:

Perbedaan jumlah kelereng atau 28 kelereng

Step-by-step explanation:

Dalam pertanyaan ini, kami memiliki dua orang yang memiliki jumlah kelereng yang berbeda. Kita tidak tahu jumlah masing-masing individu tetapi kita tahu rasio dan total. kami bertugas menemukan perbedaan jumlah kelereng yang dimiliki oleh masing-masing individu.

Untuk melakukan ini, pertama-tama kita tambahkan rasio mereka.

Ini memberi 4 + 11 = 15

Mari kita hitung pembagian Faiz, yaitu 4/15 * 60 = 16 kelereng

Bayu share adalah 11/15 * 60 = 44 kelereng.

Kami sekarang melanjutkan untuk menemukan perbedaan dalam jumlah kelereng yang dimiliki oleh keduanya.

Itu akan menjadi 44-16 = 28 kelereng

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A scuba diver swam 96 feet beneath the surface of the lake.he then climb up 49 feet .wat is the depth now?

lakkis [162]

Answer:

The depth now is 47 feet below the surface of the lake

Step-by-step explanation:

Step 1: Determine initial depth

Initial depth=surface level-depth below surface

where;

Surface level=0, since its the point of reference

depth below surface=96 feet

replacing;

Initial depth=(0-96)=-96 feet

Step 2: Final depth

Final depth=Initial depth+distance covered

where;

Initial depth=-96 feet

distance covered=+49 feet since the scuba driver moves towards the surface

replacing;

distance covered=-96+49=-47 feet

The depth now is 47 feet below the surface of the lake

5 0

3 years ago

What is the common ratio in this sequence: 3, 12, 48, 192? A. 1/4 B. -4 C. 3 D. 4

frozen [14]

I believe c is correct!!!!

4 0

3 years ago

Read 2 more answers

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

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Vladimir79 [104]

Answer:

Step-by-step explanation:

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Nitella [24]

Step-by-step explanation:

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3 years ago