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Vera_Pavlovna [14]
3 years ago
9

Which expressions are equivalent to 7b(3+c) ?

Mathematics
2 answers:
TEA [102]3 years ago
5 0

Answer:

21b+7bc

(7b⋅3)+(7b⋅c)

Step-by-step explanation:

7b(3+c)

distribute

7b* 3 + 7b *c

21b + 7bc

Alex777 [14]3 years ago
4 0

Answer:

The correct answer is B- 21b+7bc

Step-by-step explanation:

7b(3+c)

(7b)(3+c)

(7b)(3)+(7b)(c)

21b+7bc

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Step-by-step explanation:

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Read 2 more answers
The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9
mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em>h(t)<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>h(t) = 3 +90\cdot t -16\cdot t^{2}<em>, where </em>t<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

3+90\cdot t -16\cdot t^{2} = 84

16\cdot t^{2}-90\cdot t +81 = 0 (1)

By Quadratic Formula:

t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}

t_{1} = 4.5\,s, t_{2} = 1.125\,s

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

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