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zysi [14]
3 years ago
14

The angles of a pentagon are in ratio

Mathematics
2 answers:
ivanzaharov [21]3 years ago
6 0

Answer:

  216°

Step-by-step explanation:

The ratio of the sum of smallest and largest to the total of all angles is ...

  (9 +15)/(9 +10 +12 +14 +15) = 24/60 = 0.4

__

The total of all angles in an n-gon is 180°(n -2), so the total of all angles in a pentagon is ...

  180°(5 -2) = 540°

Then the sum of smallest and largest angles is ...

  0.4(540°) = 216°

Ainat [17]3 years ago
4 0
216* is the sum of measures of the smallest and largest angles
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The function f(x) = 3x² + 12x +11 can be written in
Viktor [21]

Answer:

3)  f(x) = 3(x + 2)^2 - 1.

Step-by-step explanation:

f(x) = 3x² + 12x +11

f(x) = 3(x^2 + 4x) + 11        Completing the square:

f(x) =  3[(x + 2)^2 - 4] + 11

f(x) = 3(x + 2)^2 -+3*-4 + 11

f(x) = 3(x + 2)^2  - 12 + 11

f(x) = 3(x + 2)^2 - 1.

6 0
3 years ago
A mother invests $7000 in a bank account at the time of her daughter's birth. The interest is 18) compounded quarterly at a rate
Alex

well, from birth to your twentieth birthday that'll just be 20 years, so

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$7000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &20 \end{cases} \\\\\\ A=7000\left(1+\frac{0.08}{4}\right)^{4\cdot 20}\implies A=7000(1.02)^{80}\implies A\approx 34128.07

5 0
1 year ago
.<br><br> what is the area of the pentagon shown below?
Ronch [10]

Answer:

About 80.5 feet.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Which integer is the smallest?<br> A. 34<br> B.-4<br> C.-84<br> D. 24
NISA [10]

Answer:

C. -84

Step-by-step explanation:

It is the smallest because when placed on a number line, it will be the farthest left.

5 0
1 year ago
The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
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