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3 years ago

The sum of a number and 9 is multiplied by -2 and the answer is -8

Mathematics

1 answer:

nadya68 [22]3 years ago

7 0

9(-2)+x=-8
And x would be positive 26

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Please help and show work it helps a lot thanks

Vinvika [58]

Me to I was doing the work but just lost it I will try again

8 0

2 years ago

kim owes $870.00 on her mastercard account. She returns two items costing $35.90 and $150.00 and receive credits for these on th

julsineya [31]

Answer:

She has 499.3$

Step-by-step explanation:

870+35.90+35.90+150-82.50-10-500

7 0

3 years ago

PLs i need halep fast plssssss

Delvig [45]

Answer:

b=44

b=44 - 9

b=44 + 5

x+x+x = 44

x + (x-9) + (x+5) = 44

3x - 4 = 44

3x =48

÷3

x=16

So, first photo contains 16 birds.

x=16

(x-9) - - > 16-9 = 7

(x+5) - - >16+5=21

16 + 7 + 21 =44

Answer is 16 birds in first photo

Hope this helps!

6 0

2 years ago

Would appreciate it, if anyone could help with this.

Tema [17]

Since they are intersecting lines, you would equal them to each other.
(5x+4)= (8x-71)
-8x. -8x
-3x + 4 = -71
- 4. -4
-3x = -75
Divide 3x by both sides gets you x = 25

6 0

2 years ago

Read 2 more answers

State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

7 0

2 years ago