All categories

3 years ago

PLEASE HELP ME ASAP

Mathematics

1 answer:

Phantasy [73]3 years ago

5 0

1) m=8d $40
2) d=15h 45 mi
3) less than one hour

You might be interested in

Find the produce 2 1/3 times 3 1/2

andreyandreev [35.5K]

Answer:

49/6 or 8 16/99

Step-by-step explanation:

2 1/3 *3 1/2 = (7/3*7/2)= 49/6

First convert to fraction form

then multiply across numerator to numerator and denominator to deominator

Simplify if needed

Turn to mixed fraction if needed

6 0

3 years ago

What is -0.75 - 0.4 simplified

anzhelika [568]

Answer:

-1.15

Step-by-step explanation:

Subtract 0.4 from − 0.75 .

3 0

3 years ago

Read 2 more answers

Use matrices to determine the coordinates of the vertices of the reflected figure. Then graph the pre-image and the image on the

Mashcka [7]

Answer:

The coordinates of the vertices of the reflected figure are :

R' is (-3 , -7), S' is (5 , -3), T' is (6 , 5) ⇒the right answer is figure (a)

Step-by-step explanation:

* Lets study the matrices of the reflection

- The matrix of the reflection across the x-axis is

$\left[\begin{array}{cc}1&0\\0&-1\end{array}\right]$

- Because when we reflect any point across the x-axis we

change the sign of the y-coordinate

- The matrix of the reflection across the y-axis is

$\left[\begin{array}{cc}-1&0\\0&1\end{array}\right]$

- Because when we reflect any point across the y-axis we

change the sign of the x-coordinate

* Now lets solve the problem

- We will multiply the matrix of the reflection across the x-axis

by each point to find the image of each point

- The dimension of the matrix of the reflection across the x-axis

is 2×2 and the dimension of the matrix of each point is 2×1,

then the dimension of the matrix of each image is 2×1

∵ Point R is (-3 , 7)

∴ $R'=\left[\begin{array}{cc}1&0\\0&-1\end{array}\right]\left[\begin{array}{c}-3\\7\end{array}\right]=$

$\left[\begin{array}{c}(1)(-3)+(0)(7)\\(0)(-3)+(-1)(7)\end{array}\right]=\left[\begin{array}{c}-3\\-7\end{array}\right]$

∴ R' is (-3 , -7)

∵ Point S is (5 , 3)

∴ $S'=\left[\begin{array}{cc}1&0\\0&-1\end{array}\right]\left[\begin{array}{c}5\\3\end{array}\right]=$

$\left[\begin{array}{c}(1)(5)+(0)(3)\\(0)(5)+(-1)(3)\end{array}\right]=\left[\begin{array}{c}5\\-3\end{array}\right]$

∴ S' is (5 , -3)

∵ Point T is (6 , -5)

∴ $T'=\left[\begin{array}{cc}1&0\\0&-1\end{array}\right]\left[\begin{array}{c}6\\-5\end{array}\right]=$

$\left[\begin{array}{c}(1)(6)+(0)(-5)\\(0)(6)+(-1)(-5)\end{array}\right]=\left[\begin{array}{c\pi }6\\5\end{array}\right]$

∴ T' is (6 , 5)

* Look to the answer and find the correct figure

- In figure (d) R' is (-3 , -7), S' is (5 , -3), T' is (6 , 5)

∴ The right answer is figure (a)

5 0

3 years ago

Determine if this data is an example<br> of a function.<br> (2, -4); (2, 0); (2, 1); (2, 32)

Ksenya-84 [330]

Condimentando ENCANTÁNDOSELA SUSTENTADOR

5 0

3 years ago

What are the values for the coefficients and constant term of 0 = 2 + 3x - 5x?

uranmaximum [27]

The answer is x=1 and hope that answers is very helpful

6 0

3 years ago

**PLEASE HELP ME ASAP**

PLEASE HELP ME ASAP