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sergeinik [125]
4 years ago
13

Please help!

Mathematics
1 answer:
Lostsunrise [7]4 years ago
8 0

Answer:

Using the provided formula, the amount of money Jamal have after 4 years:

A = 4253 x (1 + 1/100)^4 = 4425.69$

Hope this helps!

:)

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For which value of a does Limit of g(x) as x approaches alpha not exist?​
Hunter-Best [27]

The value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

<h3>Limit of a function</h3>

The limit of a function is the limit of a function as x tends to a value.

From the given graph, you can see that the function g(x) goes large at the point where the arrows orange and purple point down from the x-coordinates -1 and 1.

Hence the value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

Learn more on limit of a function here: brainly.com/question/23935467

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7 0
2 years ago
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
Jobisdone [24]

Answer:

f(x)=x^4-9x^2-50x-150

Step-by-step explanation:

Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).

By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.

Therefore the polynomial in factored form is f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))

We expand to get:f(x)=(x^2-2x-15)(x^2+2x+10)

We expand further to get:\

f(x)=x^4-9x^2-50x-150

3 0
3 years ago
Is x greater than, less than, or equal to 46?
Arada [10]

Answer: Less than

Step-by-step explanation:  A variables value is always 1.

3 0
3 years ago
The approximate number of Calories, C , that an animal needs each day is given by C=72m^3/4 , where m is the animal's mass in ki
Arlecino [84]

Answer:

576 Calories a 16 kilogram dog needs each day.

Step-by-step explanation:

The approximate number of Calories, C , that an animal needs each day is given by C=72m^{3/4} ,

where m is the animal's mass in kilograms.

now we find the number of Calories that a 16 kilogram dog needs each day.

we are given with m=16

So plug in 16 for m in the given equation

C=72m^{3/4}\\C=72(16)^{3/4}\\C=72(2^4)^{3/4}\\C=72(2^3)\\C= 576

576 Calories a 16 kilogram dog needs each day.

8 0
4 years ago
PLSSS NEED HELP ASAP!
Alex73 [517]
The answer is A) 1 over 2, because you take the original point such as A and go either up or down, and left or right to get to A prime
3 0
3 years ago
Read 2 more answers
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