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Virty [35]
3 years ago
13

What is the final amount if 1930 is increased by 5% followed by a further 15% increase?

Mathematics
1 answer:
fiasKO [112]3 years ago
5 0
Increased by 5%
1930*5/100= 96.5
1930+96.5=2026.5

Further increase by 15%
2026.5*15/100=303.975
2026.5+303.975=2330.475
To 2DP= 2330.48
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Answer:

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x=1/2

4 0
3 years ago
An angle that measures 90 is a(n) ____angle
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The Correct Answer Is: A
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Read 2 more answers
15+9=? (5+3) What number is missing from the expression?
Airida [17]

Answer:

<h3>\boxed{ \boxed{ \bold{  \mathsf{3}}}}</h3>

Step-by-step explanation:

Let the missing number be 'x'

⇒\mathsf{15 + 9 = x(5 + 3)}

Distribute x through the parentheses

⇒\mathsf{15 + 9 = 5x + 3x}

Swap the sides of the equation

⇒\mathsf{5x + 3x = 15 + 9}

Add the numbers

⇒\mathsf{5x + 3x = 24}

Collect like terms

⇒\mathsf{8x = 24}

Divide both sides of the equation by 8

⇒\mathsf{ \frac{8x}{8}  =  \frac{24}{8} }

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4 0
2 years ago
How can you use a strip diagram to convert 136 ounces into cups
matrenka [14]
Strip diagram is a tool that is used to be able to solve the given problem accurately.
I will show you how to do it.
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6 0
3 years ago
a radioactive sample contains 3.00 g of pure 11c, which has a half-life of 20.4 min. (a) how many moles of 11c are present initi
sveta [45]

The number of mole of pure 11C (carbon-11) initially present is 0.2727 mole

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the number of mole of pure 11C. Detail below:

<h3>How to determine the mole of 11C</h3>

From the question given, the following data were obtained:

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  • Mass of 11C = 3 g
  • Mole of 11C =?

Mole = mass / molar mass

Mole = 3 / 11

Mole = 0.2727 mole

Therefore, the number of mole of pure 11C initially present is 0.2727 mole

Learn more about mole:

brainly.com/question/13314627

#SPJ4

8 0
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